Search: id:A104101 Results 1-1 of 1 results found. %I A104101 %S A104101 4,8,15,16,23,42,108 %N A104101 The Lost Numbers. %C A104101 These numbers were central to the plot of the TV-series "Lost", episodes 18 and 201. %C A104101 Another number in the sequence, perhaps the next one, is 540: the number of days which the team of two people who are addressed by the orientation film are to stay at station 3. 4+8+15+16+23+42 = 108 * 5 = 540 - Joshua Walton (joshuawalton(AT)hotmail.com), May 05 2006 %C A104101 According to the show, 108 is not officially a part of the sequence, it just happens to be the sum of those numbers. - Ville Saalo (vsaalo(AT)iki.fi), Nov 19 2006 %C A104101 For n = 0,1,2,3,4,5 (1/120)(42n^5 - 305n^4 + 1100n^3 - 895n^2 + 1018n + 480) gives 4,12,35,89,213,511 -- the binomial transform of 4,8, 15,16,23,42. The sequence continues 1194,2622,5346,10150,18093.... The polynomial (1/120)(42x^5 - 305x^4 + 1100x^3 - 895x^2 + 1018x + 480) is the "Shaw-Basho polynomial". - Ross La Haye (rlahaye(AT)new.rr.com), Feb 26 2007 %H A104101 Dicander, M., "The Lost Numbers" The Lost Numbers: 4 8 15 16 23 42 %H A104101 Lostpedia contributors, "The Numbers", Lostpedia %H A104101 Wikipedia contributors, "Mythology of Lost", Wikipedia, The Free Encyclopedia %H A104101 Shaw, Doug, The Lost Sequence %F A104101 a(n) = (1/40)(-9n^5 + 125n^4 - 585n^3 + 1075n^2 - 446n + 160) for n = 0,1,2,3,4,5. The sequence continues 46,-52,-426,-1364,-3295... - Ross La Haye (rlahaye(AT)new.rr.com), Feb 26 2007 %Y A104101 Sequence in context: A112312 A076343 A130826 this_sequence A136403 A071422 A113902 %Y A104101 Adjacent sequences: A104098 A104099 A104100 this_sequence A104102 A104103 A104104 %K A104101 nonn,unkn %O A104101 0,1 %A A104101 Marcus Dicander (dicander(AT)kth.se), Mar 04 2005 %E A104101 a(7) from Kraig B Helberg (bethplease(AT)gmail.com), Dec 24 2005 Search completed in 0.001 seconds