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Search: id:A104536
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| A104536 |
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Let q(b-1)=k(b)*q(b)^p(b)-1 for b=n to 1, where q(n)=p(n+1), with p(x) as the x-th prime. If k(b) is the minimum positive integer that makes q(b-1) prime, then a(n)=q(0). |
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| 17, 3486013, 95546861187714408803829067490017, 11521371769146027198878540116068812681880419688486700618357345699743923465881941\ 31997252117654080689443304002035837020246444691555048358809796164736790815726144\ 90803907538033506190375184720051744203947305577550777446858943708031494162097389\ 34082646247291
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