%I A108229
%S A108229 1,2,2,2,3,3,3,3,4,4,4,4,4,4,4,5,5,5,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,
%T A108229 6,6,6,6,6,6,6,6,6,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,7,
%U A108229 7,7,7,8
%N A108229 n occurs Lucas number L(n) times (A000204).
%C A108229 This is the Lucas number equivalent of "n occurs A000045(n) times" (A072649),
which is one of an infinite number of sequences derived from the
Self-Counting Sequence [1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ... (A002024)]
which consists of 1 copy of 1, 2 copies of 2, 3 copies of 3 and so
on. These include Golomb's sequence, also known as Silverman's sequence
(A001462) and the like. As with these others, the challenge is to
give a surprisingly simple closed-form formula for a(n).
%e A108229 Because the first few Lucas numbers L(n), for n = 1, 2, 3, ... are 1,
3, 4, 7, 11, 18, 29, 47, 76, 123, the current sequence consists of
1 one, 3 twos, 4 threes, 7 fours, 11 fives, 29 sixes, 47 sevens,
76 eights, 123 nines and so on.
%Y A108229 Cf. A000204, A002024, A001462, A072649.
%Y A108229 Sequence in context: A095840 A131343 A089051 this_sequence A023966 A088141
A083291
%Y A108229 Adjacent sequences: A108226 A108227 A108228 this_sequence A108230 A108231
A108232
%K A108229 easy,nonn
%O A108229 1,2
%A A108229 Jonathan Vos Post (jvospost3(AT)gmail.com), Jul 23 2005
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