%I A110234
%S A110234 8,3,5,1,9,11,13,1,1,19,3,2,2,27,29,1,33,5,37,9,8,43,5,2,1,3,1,25,57,59,
%T A110234 61,1,65,67,6,1,8,6,11,2,81,83,5,87,9,7,3,95,1,22,27,18,15,107,16,81,8,
%U A110234 10,117,2,121,2,125,1,129,131,19,27,25,139,3,26,145,3,149,18,9,5,157,3
%N A110234 Number of consecutive integers starting with n needed to sum to a perfect 
               power.
%e A110234 a(5)=9 because 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 = 81 = 3^4, 9 consecutive 
               integers are needed.
%Y A110234 Cf. A110233, A108910.
%Y A110234 Sequence in context: A014549 A021549 A013665 this_sequence A019728 A113476 
               A124599
%Y A110234 Adjacent sequences: A110231 A110232 A110233 this_sequence A110235 A110236 
               A110237
%K A110234 easy,nonn
%O A110234 1,1
%A A110234 Jason Earls (zevi_35711(AT)yahoo.com), Jul 17 2005