Search: id:A110555 Results 1-1 of 1 results found. %I A110555 %S A110555 1,1,0,1,1,0,1,2,1,0,1,3,3,1,0,1,4,6,4,1,0,1,5,10,10,5,1,0,1,6,15,20,15, %T A110555 6,1,0,1,7,21,35,35,21,7,1,0,1,8,28,56,70,56,28,8,1,0,1,9,36,84,126,126, %U A110555 84,36,9,1,0,1,10,45,120,210,252,210,120 %V A110555 1,1,0,1,-1,0,1,-2,1,0,1,-3,3,-1,0,1,-4,6,-4,1,0,1,-5,10,-10,5,-1,0,1, -6,15,-20,15,-6, %W A110555 1,0,1,-7,21,-35,35,-21,7,-1,0,1,-8,28,-56,70,-56,28,-8,1,0,1,-9,36,-84, 126,-126,84, %X A110555 -36,9,-1,0,1,-10,45,-120,210,-252,210,-120 %N A110555 Triangle of partial sums of alternating binomial coefficients: T(n,k) = Sum(binomial(n,k)*(-1)^k: 0<=k<=n). %C A110555 T(n,0)=1, T(n,n)=0^n, T(n,k)=-T(n-1,k-1)+T(n-1,k), 00; %C A110555 T(n,2) = A000217(n-2) for n>1; %C A110555 T(n,3) = -A000292(n-4) for n>2; %C A110555 T(n,4) = A000332(n-1) for n>3; %C A110555 T(n,5) = -A000389(n-1) for n>5; %C A110555 T(n,6) = A000579(n-1) for n>6; %C A110555 T(n,7) = -A000580(n-1) for n>7; %C A110555 T(n,8) = A000581(n-1) for n>8; %C A110555 T(n,9) = -A000582(n-1) for n>9; %C A110555 T(n,10) = A001287(n-1) for n>10; %C A110555 T(n,11) = -A001288(n-1) for n>11; %C A110555 T(n,12) = A010965(n-1) for n>12; %C A110555 T(n,13) = -A010966(n-1) for n>13; %C A110555 T(n,14) = A010967(n-1) for n>14; %C A110555 T(n,15) = -A010968(n-1) for n>15; %C A110555 T(n,16) = A010969(n-1) for n>16. %C A110555 Triangle T(n,k), 0<=k<=n, read by rows, given by [1, 0, 0, 0, 0, 0, 0, 0, ...] DELTA [0, -1, 0, 0, 0, 0, 0, 0, ...] where DELTA is the operator defined in A084938 . - Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Sep 05 2005 %H A110555 Index entries for triangles and arrays related to Pascal's triangle %F A110555 T(n, k) = binomial(n-1, k)*(-1)^k, 0<=k