Search: id:A110560 Results 1-1 of 1 results found. %I A110560 %S A110560 1,3,3,5,5,7,7,1,1,11,11,13,13,1,1,17,17,19,19,1,1,23,23,1,1,1,1,29,29, %T A110560 31,31,1,1,1,1,37,37,1,1,41,41,43,43,1,1,47,47,1,1,1,1,53,53,1,1,1,1,59, %U A110560 59,61,61,1,1,1,1,67,67,1,1,71,71,73,73,1,1,1,1,79,79,1,1,83,83 %N A110560 Numerators of T(n+1)/n! reduced to lowest terms, where T(n) are the triangular numbers A000217. %C A110560 The exponential generating function of the triangular numbers ws given in Sloane & Plouffe as g(x) = (1 + 2x + (x^2)/2)*e^x = 1 + 3*x + 3*x^2 + (5/3)*x^3 + (5/8)*x^4 + (7/40)*x^5 + (1/896)*x^6 + (11/72576)*x^7 + ... = 1 + 3*x/1! + 6*(x^2)/2! + 10*(x^3)/3! + 15*(x^4)/4! + ... %D A110560 Sloane, N. J. A. and Plouffe, S. The Encyclopedia of Integer Sequences. San Diego, CA: Academic Press, 1995, p. 9. %H A110560 Eric Weisstein's World of Mathematics, Triangular Number. %F A110560 A110560(n)/A110561(n) is the n-th coefficient of the exponential generating function of T(n), the triangular numbers A000217. %e A110560 a(3) = 5 because T(3+1)/3! = T(4)/3! = (4*5/2)/(1*2*3) = 10/6 = 5/3 so the fraction has numerator 5 and denominator A110561(3) = 3. Furthermore, the 3rd term of the exponential generating function of the triangular numbers is (5/3)*x^3. %t A110560 T[n_] := n*(n + 1)/2; Table[Numerator[T[n + 1]/n! ], {n, 0, 82}] %Y A110560 Denominator = A110561. %Y A110560 Closely related to this is T(n)/n! which is A090585/A090586. %Y A110560 Sequence in context: A021302 A004649 A002374 this_sequence A141424 A069902 A085779 %Y A110560 Adjacent sequences: A110557 A110558 A110559 this_sequence A110561 A110562 A110563 %K A110560 easy,frac,nonn %O A110560 0,2 %A A110560 Jonathan Vos Post (jvospost3(AT)gmail.com), Jul 27 2005 %E A110560 Extended by Ray Chandler (rayjchandler(AT)sbcglobal.net), Jul 27 2005 Search completed in 0.001 seconds