Search: id:A112974
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%I A112974
%S A112974 1,0,3,0,2,4,0,4,6,0,2,3,6,8,6,0,10,10,5,2,11,9,10,0,9,10,12,4,13,14,15,
%T A112974 11,6,14,0,12,2,12,11,5,10,11,12,12,12,11,11,13,13,0,15,14,3,14,16,16,
               8,
%U A112974 16,17,17,19,20,16,14,7,16,2,16,14,15,3,15,15,14,18,0,16,16,16,16,16,14
%N A112974 Number of superabundant numbers between two consecutive colossally abundant 
               numbers.
%C A112974 The colossally abundant numbers are a subset of the superabundant abundant 
               numbers. Is there a formula for a(n) that depends on the two consecutive 
               colossally abundant numbers A004490(n) and A004490(n+1)?
%H A112974 T. D. Noe, <a href="b112974.txt">Table of n, a(n) for n=1..10000</a>
%e A112974 a(3)=3 because between colossally abundant numbers 12 and 60 there are 
               three superabundant numbers: 24, 36 and 48.
%Y A112974 Cf. A004490 (colossally abundant numbers), A004394 (superabundant numbers).
%Y A112974 Sequence in context: A112455 A001608 A159977 this_sequence A113069 A136163 
               A058624
%Y A112974 Adjacent sequences: A112971 A112972 A112973 this_sequence A112975 A112976 
               A112977
%K A112974 nonn
%O A112974 1,3
%A A112974 T. D. Noe (noe(AT)sspectra.com), Oct 07 2005

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