Search: id:A113503 Results 1-1 of 1 results found. %I A113503 %S A113503 1,1,0,2,0,0,0,3,1,1,0,1,0,0,0,6,2,2,0,2,0,0,0,2,0,0,0,0,0,0,0,10,3, %T A113503 4,0,4,0,0,0,4,0,0,0,0,0,0,0,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,14,4,4, %U A113503 1,4,1,1,0,4,1,1,0,1,0,0,0,4,1,1,0,1,0,0,0,1,0,0,0,0,0,0,0,4,1,1,0 %N A113503 a(1) = 1. For n >= 2, a(n) = number of earlier terms of the sequence that have the same number of ones in their binary representations as n. %H A113503 Diana Mecum, Table of n, a(n) for n = 1..210 %H A113503 Leroy Quet, Home Page (listed in lieu of email address) %e A113503 The first 7 terms written in binary are [1,1,0,10,0,0,0]. The 8th term gives the number of earlier terms with the same number of 1's in their binary representation as 8 (which is 1000 in binary, for one 1). a(8) = 3 because there are three terms among the first 7 terms with one binary 1 (terms with one 1: 1, 1 and 2). %Y A113503 Cf. A113504, A000120. %Y A113503 Sequence in context: A076849 A083059 A046268 this_sequence A082507 A132349 A123391 %Y A113503 Adjacent sequences: A113500 A113501 A113502 this_sequence A113504 A113505 A113506 %K A113503 nonn %O A113503 1,4 %A A113503 Leroy Quet, Jan 10 2006 %E A113503 More terms from Diana Mecum (diana.mecum(AT)gmail.com), May 29 2007 Search completed in 0.002 seconds