Search: id:A113503
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%I A113503
%S A113503 1,1,0,2,0,0,0,3,1,1,0,1,0,0,0,6,2,2,0,2,0,0,0,2,0,0,0,0,0,0,0,10,3,
%T A113503 4,0,4,0,0,0,4,0,0,0,0,0,0,0,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,14,4,4,
%U A113503 1,4,1,1,0,4,1,1,0,1,0,0,0,4,1,1,0,1,0,0,0,1,0,0,0,0,0,0,0,4,1,1,0
%N A113503 a(1) = 1. For n >= 2, a(n) = number of earlier terms of the sequence
that have the same number of ones in their binary representations
as n.
%H A113503 Diana Mecum, Table of n, a(n) for n = 1..210
%H A113503 Leroy Quet, Home Page
(listed in lieu of email address)
%e A113503 The first 7 terms written in binary are [1,1,0,10,0,0,0]. The 8th term
gives the number of earlier terms with the same number of 1's in
their binary representation as 8 (which is 1000 in binary, for one
1). a(8) = 3 because there are three terms among the first 7 terms
with one binary 1 (terms with one 1: 1, 1 and 2).
%Y A113503 Cf. A113504, A000120.
%Y A113503 Sequence in context: A076849 A083059 A046268 this_sequence A082507 A132349
A123391
%Y A113503 Adjacent sequences: A113500 A113501 A113502 this_sequence A113504 A113505
A113506
%K A113503 nonn
%O A113503 1,4
%A A113503 Leroy Quet, Jan 10 2006
%E A113503 More terms from Diana Mecum (diana.mecum(AT)gmail.com), May 29 2007
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