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Search: id:A113503
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| A113503 |
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a(1) = 1. For n >= 2, a(n) = number of earlier terms of the sequence that have the same number of ones in their binary representations as n. |
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2
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| 1, 1, 0, 2, 0, 0, 0, 3, 1, 1, 0, 1, 0, 0, 0, 6, 2, 2, 0, 2, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 10, 3, 4, 0, 4, 0, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 14, 4, 4, 1, 4, 1, 1, 0, 4, 1, 1, 0, 1, 0, 0, 0, 4, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 4, 1, 1, 0
(list; graph; listen)
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OFFSET
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1,4
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LINKS
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Diana Mecum, Table of n, a(n) for n = 1..210
Leroy Quet, Home Page (listed in lieu of email address)
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EXAMPLE
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The first 7 terms written in binary are [1,1,0,10,0,0,0]. The 8th term gives the number of earlier terms with the same number of 1's in their binary representation as 8 (which is 1000 in binary, for one 1). a(8) = 3 because there are three terms among the first 7 terms with one binary 1 (terms with one 1: 1, 1 and 2).
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CROSSREFS
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Cf. A113504, A000120.
Sequence in context: A076849 A083059 A046268 this_sequence A082507 A132349 A123391
Adjacent sequences: A113500 A113501 A113502 this_sequence A113504 A113505 A113506
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KEYWORD
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nonn
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AUTHOR
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Leroy Quet, Jan 10 2006
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EXTENSIONS
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More terms from Diana Mecum (diana.mecum(AT)gmail.com), May 29 2007
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