Search: id:A113504 Results 1-1 of 1 results found. %I A113504 %S A113504 1,1,2,0,3,1,1,0,5,2,2,0,2,0,0,0,8,2,2,0,2,0,0,0,2,0,0,0,0,0,0,0,13,2, 2, %T A113504 1,2,1,1,0,2,1,1,0,1,0,0,0,2,1,1,0,1,0,0,0,1,0,0,0,0,0,0,0,28,2,2,2,2, 2, %U A113504 2,0,2,2,2,0,2,0,0,0,2,2,2,0,2,0,0,0,2,0,0,0,0,0,0,0,2,2,2,0,2,0,0,0,2 %N A113504 a(0) = 1. For n >= 1, a(n) = number of earlier terms of the sequence that have the same number of ones in their binary representations as n. %C A113504 A115211(n) = A00120(a(n)) = number of ones in binary representation of a(n) for n>0; record values: A115212(n) = a(A115213(n)). - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jan 17 2006 %H A113504 Leroy Quet, Home Page (listed in lieu of email address) %e A113504 The first 8 terms (terms 0 through 7) written in binary are [1,1,10,0, 11,1,1,0]. Term 8 gives the number of earlier terms with the same number of 1's in their binary representation as 8 (which is 1000 in binary, for one 1). a(8) = 5 because there are five terms among the earlier terms with one binary 1 (terms with one 1: 1, 1, 2, 1 and 1). %Y A113504 Cf. A113503, A000120. %Y A113504 Sequence in context: A144955 A002187 A124756 this_sequence A124754 A047983 A070812 %Y A113504 Adjacent sequences: A113501 A113502 A113503 this_sequence A113505 A113506 A113507 %K A113504 nonn %O A113504 0,3 %A A113504 Leroy Quet, Jan 10 2006 %E A113504 More terms from Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jan 17 2006 Search completed in 0.001 seconds