Search: id:A113534 Results 1-1 of 1 results found. %I A113534 %S A113534 1,3,4,7,20,10,39,12,26,19,20,43 %N A113534 Ascending descending base exponent transform of the flipped tribonacci substitution (A092782). %C A113534 The flipped tribonacci substitution (A092782) b(n) is the fixed point of the morphism 1 -> 12, 2 -> 13, 3 -> 1, starting from b(1) = 1. The transformed sequence a(n) satisfies n =< a(n) =< 27 n but the bound can be determined to be much tighter. %D A113534 V. F. Sirvent, Semigroups and the self-similar structure of the flipped tribonacci substitution, Applied Math. Letters, 12 (1999), 25-29. [Contains many further references.] %e A113534 a(1) = A092782(1)^A092782(1) = 1^1 = 1. %e A113534 a(2) = A092782(1)^A092782(2) + A092782(2)^A092782(1) = 1^2 + 2^1 = 3. %e A113534 a(3) = 1^1 + 2^2 + 1^1 = 4. %e A113534 a(4) = 1^3 + 2^1 + 1^2 + 3^1 = 7. %e A113534 a(5) = 1^1 + 2^3 + 1^1 + 3^2 + 1^1 = 20. %e A113534 a(6) = 1^2 + 2^1 + 1^3 + 3^1 + 1^2 + 2^1 = 10. %e A113534 a(7) = 1^1 + 2^2 + 1^1 + 3^3 + 1^1 + 2^2 + 1^1 = 39. %e A113534 a(8) = 1^1 + 2^1 + 1^2 + 3^1 + 1^3 + 2^1 + 1^2 + 1^1 = 12. %e A113534 a(9) = 1^2 + 2^1 + 1^1 + 3^2 + 1^1 + 2^3 + 1^1 + 1^2 + 2^1 = 26. %e A113534 a(10) = 1^1 + 2^2 + 1^1 + 3^1 + 1^2 + 2^1 + 1^3 + 1^1 + 2^2 + 1^1 = 19. %e A113534 a(11) = 1^3 + 2^1 + 1^2 + 3^1 + 1^1 + 2^2 + 1^1 + 1^3 + 2^1 + 1^2 + 3^1 = 20. %e A113534 a(12) = 1^1 + 2^3 + 1^1 + 3^2 + 1^1 + 2^1 + 1^2 + 1^1 + 2^3 + 1^1 + 3^2 + 1^1 = 43. %Y A113534 Cf. A092782, A113320, A005408, A113122, A113153, A113154, A113336, A113271, A113258, A113257, A113231, A087316, A113208, A113498. %Y A113534 Sequence in context: A041497 A042227 A117789 this_sequence A030724 A124082 A056655 %Y A113534 Adjacent sequences: A113531 A113532 A113533 this_sequence A113535 A113536 A113537 %K A113534 easy,nonn %O A113534 1,2 %A A113534 Jonathan Vos Post (jvospost3(AT)gmail.com), Jan 13 2006 Search completed in 0.001 seconds