Search: id:A113535
Results 1-1 of 1 results found.

%I A113535
%S A113535 1,3,8,19,32,9,11,16,26,19,29,24
%N A113535 Ascending descending base exponent transform of the tribonacci substitution 
               (A100619).
%C A113535 Sirvent comments that in spite of the similarity of this map to the one 
               in A092782, the two sequences have very different properties. They 
               have different complexities, different Rauzy fractals, etc.
%D A113535 V. F. Sirvent, Semigroups and the self-similar structure of the flipped 
               tribonacci substitution, Applied Math. Letters, 12 (1999), 25-29. 
               [Contains many further references.]
%e A113535 a(1) = A100619(1)^A100619(1) = 1^1 = 1.
%e A113535 a(2) = A100619(1)^A100619(2) + A100619(2)^A100619(1) = 1^2 + 2^1 = 3.
%e A113535 a(3) = 1^3 + 2^2 + 3^1 = 8.
%e A113535 a(4) = 1^1 + 2^3 + 3^2 + 1^1 = 19.
%e A113535 a(5) = 1^1 + 2^1 + 3^3 + 1^2 + 1^1 = 32.
%e A113535 a(6) = 1^1 + 2^1 + 3^1 + 1^3 + 1^2 + 1^1 = 9.
%e A113535 a(7) = 1^2 + 2^1 + 3^1 + 1^1 + 1^3 + 1^2 + 2^1 = 11.
%e A113535 a(8) = 1^1 + 2^2 + 3^1 + 1^1 + 1^1 + 1^3 + 2^2 + 1^1 = 16.
%e A113535 a(9) = 1^1 + 2^1 + 3^2 + 1^1 + 1^1 + 1^1 + 2^3 + 1^2 + 2^1 = 26.
%e A113535 a(10) = 1^1 + 2^2 + 3^1 + 1^2 + 1^1 + 1^1 + 2^1 + 1^3 + 2^2 + 1^1 = 19.
%e A113535 a(11) = 1^2 + 2^1 + 3^2 + 1^1 + 1^2 + 1^1 + 2^1 + 1^1 + 2^3 + 1^2 + 2^1 
               = 29.
%e A113535 a(12) = 1^3 + 2^2 + 3^1 + 1^2 + 1^1 + 1^2 + 2^1 + 1^1 + 2^1+ 1^3 + 2^2 
               + 3^1 = 24.
%Y A113535 Cf. A100619, A092782, A103269, A113320, A005408, A113122, A113153, A113154, 
               A113336, A113271, A113258, A113257, A113231, A087316, A113208, A113498.
%Y A113535 Sequence in context: A091109 A123982 A171308 this_sequence A139020 A147358 
               A086167
%Y A113535 Adjacent sequences: A113532 A113533 A113534 this_sequence A113536 A113537 
               A113538
%K A113535 easy,nonn
%O A113535 1,2
%A A113535 Jonathan Vos Post (jvospost3(AT)gmail.com), Jan 13 2006

Search completed in 0.001 seconds