Search: id:A115026 Results 1-1 of 1 results found. %I A115026 %S A115026 1,2,3,4,5,6,7,8,9,1,2,5,1,370,370,370,370,370,1,4,5,8,1,4,370,370,370, %T A115026 1,370,9,1,1,370,370,370,370,370,370,370,370,370,4,370,1,370,370,370, %U A115026 370,1,370,370,370,370,370,370,370,370,370,160,370,370,370,370,370,370 %N A115026 Limiting value of n under iteration of "sum of the digits raised to the power of the number of digits of n" (A101337). %C A115026 Iterate A101337 starting at n until reaching a constant value (like 370) or a cycle (like 160, 217, 352, 160...). In the latter case a(n) takes the smallest value in the cycle (e.g. a(59) = 160). Since k*9^k < 10^k for all k>34, then each number n is guaranteed to yield a smaller number a(n) if n > 10^34, so every number reaches a constant or a cycle under this sequence. %e A115026 E.g. a(89)=370 since: %e A115026 89 (2 digits): 8^2 + 9^2 = 145 %e A115026 145 (3 digits): 1^3 + 4^3 + 5^3 = 190 %e A115026 190 (3 digits): 1^3 + 9^3 + 0^3 = 730 %e A115026 730 (3 digits): 7^3 + 3^3 + 0^3 = 370 %e A115026 370 (3 digits): 3^3 + 7^3 + 0^3 = 370...etc %e A115026 So a(89) = 370 since 370 is a constant value under this series. %Y A115026 Cf. A101337. %Y A115026 Sequence in context: A007953 A080463 A114570 this_sequence A101337 A135208 A156207 %Y A115026 Adjacent sequences: A115023 A115024 A115025 this_sequence A115027 A115028 A115029 %K A115026 nonn %O A115026 1,2 %A A115026 Sergio Pimentel (ferdiego(AT)cox.net), Feb 24 2006 Search completed in 0.001 seconds