Search: id:A118106
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%I A118106
%S A118106 1,1,1,1,1,2,1,1,1,4,1,2,1,3,4,1,1,6,1,4,6,10,1,2,1,12,1,6,1,4,1,1,10,
8,
%T A118106 12,6,1,18,3,4,1,6,1,10,12,11,1,4,1,20,16,12,1,18,5,6,18,28,1,4,1,5,6,
1,
%U A118106 4,10,1,8,22,12,1,6,1,36,20,18,30,12,1,4,1,20,1,6,16,14,28,10,1,12,12
%N A118106 Period of the vector sequence d(n)^k mod n for k=1,2,3,..., where d(n)
is the vector of divisors of n.
%C A118106 This sequence is related to the period of sigma_k(n) mod n. Note that
a(n)=1 iff n is a power of a prime.
%C A118106 The record period lengths of p-1 occur at n=2p, where p is a prime with
primitive root 2 (A001122). - T. D. Noe, Oct 25 2007
%H A118106 T. D. Noe, Table of n, a(n) for n=1..1000
%e A118106 a(35)=12 because d(35)=(1,5,7,35) and (1,5,7,35)^k (mod 35) is the sequence
of vectors (1,5,7,0), (1,25,14,0), (1,20,28,0), (1,30,21,0), (1,10,
7,0), (1,15,14,0), (1,5,28,0), (1,25,21,0), (1,20,7,0), (1,30,14,
0), (1,10,28,0), (1,15,21,0), (1,5,7,0),..., which has a period of
12.
%t A118106 Table[d=Divisors[n]; k=0; found=False; While[i=0; While[i