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A118654 Matrix, a(n,k) = 2^n(Fibonacci(k)) - Fibonacci(k-2), read by anti-diagonals. +0
15
1, 1, 0, 1, 1, 1, 1, 3, 2, 1, 1, 7, 4, 3, 2, 1, 15, 8, 7, 5, 3, 1, 31, 16, 15, 11, 8, 5, 1, 63, 32, 31, 23, 18, 13, 8, 1, 127, 64, 63, 47, 38, 29, 21, 13, 1, 255, 128, 127, 95, 78, 61, 47, 34, 21, 1, 511, 256, 255, 191, 158, 125, 99, 76, 55, 34 (list; table; graph; listen)
OFFSET

0,8

COMMENT

Inverse binomial transform (by columns) of A090888.

FORMULA

a(n,k) = 2^n(Fibonacci(k)) - Fibonacci(k-2). a(n,k) = (2^n-2)Fibonacci(k) + Fibonacci(k+1). a(n,0) = 1; a(n,1) = 2^n - 1; a(n,k) = a(n,k-1) + a(n,k-2), for k > 1. a(0,k) = Fibonacci(k-1); a(1,k) = Fibonacci(k+1); a(n,k) = 3a(n-1,k) - 2a(n-2,k), for n > 1. a(n,k) = 2a(n-1,k) + Fibonacci(k-2), for n > 0. O.g.f. (by rows) = (1+(-2+2^n)x)/(1-x-x^2).

Sum[a(n-k, k), {k, 0, n}] = A119587(n+1). - Ross La Haye (rlahaye(AT)new.rr.com), May 31 2006 Ross

EXAMPLE

a(2,3) = 7 because 2^2(Fibonacci(3)) - Fibonacci(3-2) = 4*2 - 1 = 7.

{1}; {1,0}; {1,1,1}; {1,3,2,1}; {1,7,4,3,2}; {1,15,8,7,5,3}; {1,31,16,15,11,8,5}; {1,63,32,31,23,18,13,8}.

CROSSREFS

Cf. a(n, k) = A109754(2^n-2, k+1) = A101220(2^n-2, 0, k+1), for n > 0. Rows: a(0, k) = A000045(k-1), for k > 0; a(1, k) = A000045(k+1); a(2, k) = A000032(k+1); a(3, k) = A022097(k); a(4, k) = A022105(k); a(5, k) = A022401(k). Columns: a(n, 1) = A000225(n); a(n, 2) = A000079(n); a(n, 3) = A000225(n+1); a(n, 4) = A055010(n+1); a(n, 5) = A051633(n); a(n, 6) = A036563(n+3).

Sequence in context: A113185 A132069 A073201 this_sequence A111760 A078424 A092742

Adjacent sequences: A118651 A118652 A118653 this_sequence A118655 A118656 A118657

KEYWORD

nonn,tabl

AUTHOR

Ross La Haye (rlahaye(AT)new.rr.com), May 17 2006

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Last modified December 16 17:18 EST 2009. Contains 170825 sequences.


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