Search: id:A119913 Results 1-1 of 1 results found. %I A119913 %S A119913 0,0,2,14,74,394,2344,16036,125628,1112028,10976118,119481218, %T A119913 1421542550 %N A119913 Number of different simple cycles in the complete graph K_n; that is, the number of subsets of at least 3 elements out of n, ordered up to cyclic permutations. %F A119913 a(n) = Sum_{k=3..n} (n choose k) * (k-1)! ; a(n) = Sum_{i=2..n-1}(Floor(e*i!)) - (n+3)(n-2)/2 ; a(n) = Sum_{k=1..n-1} A038154(k) %F A119913 a(n) = 2*A002807(n). - Vladeta Jovovic (vladeta(AT)eunet.rs), Aug 04 2006 %e A119913 a(4)=14 because there are 6 4-cycles and 8 3-cycles. %o A119913 Matlab: function a = an(n) s = 0; for i = 2:n-1 s = s+fix(exp(1)*factorial(i)); end a = s - (n+3)*(n-2)/2; %Y A119913 Cf. A038154. %Y A119913 Sequence in context: A095933 A043011 A138156 this_sequence A104871 A034573 A133224 %Y A119913 Adjacent sequences: A119910 A119911 A119912 this_sequence A119914 A119915 A119916 %K A119913 nonn %O A119913 1,3 %A A119913 Amir M. Ben-Amram (amirben(AT)mta.ac.il), Aug 02 2006 Search completed in 0.001 seconds