Search: id:A121389
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%I A121389
%S A121389 0,9,9,99,999,99999,99999999,9999999999999,999999999999999999999,
%T A121389 9999999999999999999999999999999999,
%U A121389 9999999999999999999999999999999999999999999999999999999
%N A121389 10^Fibonacci(n) - 1.
%C A121389 Each a(n) has Fibonacci(n) (trailing) 9s. In general, if the same recurrence 
               below is used with any a(0), a(1) >= 0, then, for all k >= 2, a(k) 
               has the same number of trailing 9s as a(k-2) and a(k-1) have altogether. 
               (See, for example, A121390).
%F A121389 a(n) = 10^Fibonacci(n) - 1 = 10^A000045(n) - 1 (= 9*A108047(n) for n>
               =1). a(0) = 0; a(1) = 9; a(n) = a(n-2)*a(n-1) + a(n-2) + a(n-1).
%Y A121389 Cf. A000045, A063896, A108047, A121390.
%Y A121389 Sequence in context: A165427 A050683 A092548 this_sequence A065242 A050720 
               A124116
%Y A121389 Adjacent sequences: A121386 A121387 A121388 this_sequence A121390 A121391 
               A121392
%K A121389 nonn
%O A121389 0,2
%A A121389 Rick L. Shepherd (rshepherd2(AT)hotmail.com), Jul 26 2006

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