%I A126336
%S A126336 1,1,2,2,2,3,2,4,3,4,1,11,6,3,1,7,2,8,2,2,92,9,1,1,6,2,1,1,2,2,1,1,1,1,
%T A126336 1,2,1,2,22,3,5,2,3,1,1,15,3,4,2,26,1,7,12,1,7,2,1,26,1,1,4,33,13,1,5,
               1,
%U A126336 13,1,8,1,13,1,18,2,39,4,1,2,10,6,1,4,1,20,43,1,1,3,1,21,1,1,2,2,49,1
%N A126336 Irregular table where the first row is (1). Row n is the continued fraction 
               terms of the rational equal to the sum of the reciprocals of all 
               the terms in the previous rows.
%C A126336 The continued fractions, for rows 3 and up, each have a final term >=2. 
               The number of terms in the n-th row is A126337(n). The sum of the 
               reciprocals of the terms in rows 1 through n is A126338(n)/A126339(n).
%H A126336 Leroy Quet, <a href="http://www.prism-of-spirals.net/">Home Page</a> 
               (listed in lieu of email address)
%e A126336 The sum of the reciprocals of the terms of the first 6 rows is 1 +1 +1/
               2 +1/2 +1/ 2 +1/3 +1/2 +1/4 +1/3 = 59/12. 59/12 equals the continued 
               fraction 4 +1/(1 +1/11). So row 7 is (4,1,11).
%t A126336 f[l_List] := Append[l, ContinuedFraction[Plus @@ (1/# &) /@ Flatten[l]]]Flatten@Nest[f, 
               {{1}}, 15] (*Chandler*)
%Y A126336 Cf. A126337, A126338, A126339.
%Y A126336 Sequence in context: A076709 A110021 A036013 this_sequence A134446 A125749 
               A014085
%Y A126336 Adjacent sequences: A126333 A126334 A126335 this_sequence A126337 A126338 
               A126339
%K A126336 easy,nonn,tabf
%O A126336 1,3
%A A126336 Leroy Quet Dec 25 2006
%E A126336 Extended by Ray Chandler (rayjchandler(AT)sbcglobal.net), Dec 26 2006