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A127268 If the prime-factorization of n is n = product{p|n} p^b(p,n) (p = distinct primes divisors of n, each b(p,n) is a positive integer), then a(n) is (sum{p|n} p^b(p,n)) taken mod (sum{p|n} p). +0
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0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 1, 0, 2, 0, 0, 0, 1, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 3, 0, 0, 0, 6, 0, 0, 0, 2, 6, 0, 0, 4, 0, 6, 0, 2, 0, 4, 0, 6, 0, 0, 0, 2, 0, 0, 6, 0, 0, 0, 0, 2, 0, 0, 0, 2, 0, 0, 4, 2, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 6, 0, 6, 0, 2, 0, 0, 0, 0, 0, 6, 6, 1 (list; graph; listen)
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Last modified November 30 13:13 EST 2009. Contains 167758 sequences.


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