Search: id:A128064
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%I A128064
%S A128064 1,1,2,0,2,3,0,0,3,4,0,0,0,4,5,0,0,0,0,5,6,0,0,0,0,0,6,7,0,0,0,0,0,0,7,
%T A128064 8
%V A128064 1,-1,2,0,-2,3,0,0,-3,4,0,0,0,-4,5,0,0,0,0,-5,6,0,0,0,0,0,-6,7,0,0,0,0,
               0,0,-7,8
%N A128064 A natural number transform.
%C A128064 The matrix inverse = (1/1; 1/2, 1/2; 1/3, 1/3, 1/3;...). Binomial transform 
               of A128064 = A128065 A128064 * A007318 = A103406
%C A128064 The positive version with row sums 2n+1 is given by T(n,k)=sum{j=k..n, 
               C(n,j)*C(j,k)*(-1)^(n-j)*(j+1)}. - Paul Barry (pbarry(AT)wit.ie), 
               May 26 2007
%C A128064 Binomial transform of unsigned sequence is A003506. - Gary W. Adamson 
               (qntmpkt(AT)yahoo.com), Aug 29 2007
%F A128064 Triangle read by rows: row 1 = 1, row 2 = (-1, 2); (n-2) zeros followed 
               by -(n-1), n. Infinite lower triangular matrix with (1, 2, 3,...) 
               as the right border, (-1, -2, -3,...) as the adjacent diagonal and 
               the rest zeros.
%F A128064 Number triangle T(n,k)=sum{j=k..n, C(n,j)*C(j,k)*(-1)^(j-k)*(j+1)} - 
               Paul Barry (pbarry(AT)wit.ie), May 26 2007
%e A128064 First few rows of the triangle are:
%e A128064 1;
%e A128064 -1, 2;
%e A128064 0, -2, 3;
%e A128064 0, 0, -3, 4;
%e A128064 0, 0, 0, -4, 5;
%e A128064 ...
%Y A128064 Cf. A128065, A103406.
%Y A128064 Cf. A003506.
%Y A128064 Sequence in context: A053571 A129883 A098489 this_sequence A144217 A132814 
               A058623
%Y A128064 Adjacent sequences: A128061 A128062 A128063 this_sequence A128065 A128066 
               A128067
%K A128064 tabl,sign
%O A128064 1,3
%A A128064 Gary W. Adamson (qntmpkt(AT)yahoo.com), Feb 14 2007

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