Search: id:A128834 Results 1-1 of 1 results found. %I A128834 %S A128834 0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1, %T A128834 1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0, %U A128834 1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1 %V A128834 0,1,1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1, 0,1,1,0,-1,-1,0, %W A128834 1,1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1,0, 1,1,0,-1,-1,0,1, %X A128834 1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1,0,1,1,0,-1,-1,0,1, 1 %N A128834 Periodic sequence 0,1,1,0,-1,-1,... %C A128834 Unsigned version in A011655 . %F A128834 a(0)=0, a(1)=1,a(n+1)=a(n)-a(n-1) for n>=1 . G.f.:x*(1+x)/(1+x^3) . %F A128834 Euler transform of length 6 sequence [ 1, -1, -1, 0, 0, 1]. - Michael Somos Apr 15 2007 %F A128834 G.f. A(x) satisfies 0= f(A(x), A(x^2)) where f(u, v)= v -u^2 +2*u*v -2*u^2*v . - Michael Somos Apr 15 2007 %F A128834 G.f. A(x) satisfies 0= f(A(x), A(x^3)) where f(u, v)= v -u^3 +3*u*v -3*u^3*v . - Michael Somos Apr 15 2007 %F A128834 a(n)=(1/6)*{-(n mod 6)+[(n+2) mod 6]+[(n+3) mod 6]-[(n+5) mod 6]}, with n>=0 - Paolo P. Lava (ppl(AT)spl.at), Jun 11 2007 %F A128834 a(n) = A010892(n-1) . - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Feb 08 2008 %F A128834 a(n) is multiplicative with a(3^e) = 0^e, a(p^e) = 1 if p == 1 (mod 3), a(p^e) = (-1)^e if p == 2 (mod 3) . - Michael Somos Apr 15 2007 %F A128834 a(n)=2sin(n*pi/3)/sqrt(3) [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Dec 05 2008] %e A128834 x + x^2 - x^4 - x^5 + x^7 + x^8 - x^10 - x^11 + x^13 + x^14 - x^16 + ... %o A128834 (PARI) {a(n)= [0, 1, 1, 0, -1, -1][n%6 +1]} %Y A128834 a(n)=A010892(n+5) [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Dec 05 2008] %Y A128834 Sequence in context: A092220 A011655 A102283 this_sequence A022928 A000494 A022933 %Y A128834 Adjacent sequences: A128831 A128832 A128833 this_sequence A128835 A128836 A128837 %K A128834 sign,mult %O A128834 0,1 %A A128834 Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Apr 13 2007 Search completed in 0.002 seconds