Search: id:A130198 Results 1-1 of 1 results found. %I A130198 %S A130198 0,1,0,0,1,0,1,1,0,1,0,0,1,0,1,1,0,1,0,0,1,0,1,1,0,1,0,0,1,0,1,1,0,1,0, %T A130198 0,1,0,1,1,0,1,0,0,1,0,1,1,0,1,0,0,1,0,1,1,0,1,0,0,1,0,1,1,0,1,0,0,1,0, %U A130198 1,1,0,1 %N A130198 Single paradiddlde. In percussion, the paradiddle is a four-note drum sticking pattern consisting of two alternating notes followed by two notes on the same hand. %C A130198 Also the binary expansion of the constant 5/17 = 2^(-2)+2^(-5)+2^(-7)+... [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Mar 27 2009] %H A130198 Wikipedia, Paradiddle %F A130198 a(n)=(1/56)*{8*(n mod 8)+[(n+1) mod 8]-6*[(n+2) mod 8]+8*[(n+3) mod 8]-6*[(n+4) mod 8]+[(n+5) mod 8]+8*[(n+6) mod 8]-6*[(n+7) mod 8]}, with n>=0. - Paolo P. Lava (ppl(AT)spl.at), Nov 09 2007 %F A130198 a(n)=a(n-8)=a(n-1)-a(n-4)+a(n-5). G.f.: -x*(1+x^3-x)/((x-1)*(1+x^4). [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Mar 27 2009] %o A130198 (PARI) a(n)=((n%8>3)+(n%4==1))%2 [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Mar 19 2009] %o A130198 (PARI) a(n)=210\2^(n%8)%2; [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Mar 24 2009] %Y A130198 Cf. A121262, A131078. [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Mar 19 2009] %Y A130198 Sequence in context: A059620 A083651 A111748 this_sequence A104893 A104894 A071986 %Y A130198 Adjacent sequences: A130195 A130196 A130197 this_sequence A130199 A130200 A130201 %K A130198 nonn %O A130198 0,1 %A A130198 Simone Severini (simoseve(AT)gmail.com), May 16 2007 Search completed in 0.001 seconds