Search: id:A130247 Results 1-1 of 1 results found. %I A130247 %S A130247 1,0,2,3,3,3,4,4,4,4,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6,6,7,7,7,7,7,7,7, %T A130247 7,7,7,7,7,7,7,7,7,7,7,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8, %U A130247 8,8,8,8,8,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9 %N A130247 Inverse Lucas (A000032) numbers: index k of a Lucas number such that Lucas(k)=n; max(k|Lucas(k)=0 (see A130241 and A130242 for other versions). Same as A130241 except for n=1. %F A130247 a(n)=c(n), if (n^2-4)/5 is a square number, a(n)=s(n), if (n^2+4)/5 is a square number and a(n)=floor(log_phi(n)) else, where s(n)=floor(arsinh(n/ 2)/ln(phi)), c(n)=floor(arcosh(n/2)/ln(phi)) and phi=(1+sqr(5))/2. %F A130247 a(n)=A130241(n) except for n=2. %F A130247 G.f.: g(x)=1/(1-x)*sum{k>=1, x^Lucas(k)}-x^2. %F A130247 a(n)=floor(log_phi(n+1/2)) for n>=3, where phi is the golden ratio. %e A130247 a(2)=0, since Lucas(0)=2; a(10)=4, since Lucas(4)=7<10 but Lucas(5)=11> 10. %Y A130247 For partial sums see A130248. Other related sequences: A000032, A130241, A130242, A130245, A130249, A130255, A130259. Indicator sequence A102460. Fibonacci inverse see A130233 - A130240, A104162. %Y A130247 Sequence in context: A117806 A085423 A130241 this_sequence A087839 A106742 A106733 %Y A130247 Adjacent sequences: A130244 A130245 A130246 this_sequence A130248 A130249 A130250 %K A130247 nonn %O A130247 1,3 %A A130247 Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), May 19 2007, Jul 02 2007 Search completed in 0.001 seconds