Search: id:A132181 Results 1-1 of 1 results found. %I A132181 %S A132181 1,2,6,1,28,1,1,58,1,708,1,1,2,1,2836,1,1,22696,1,1,1,590122,1,12,1,1, 2, %T A132181 1,1180246,1,9441976,1,1,1,169955586,1,2,1,2,1,2719289392,1,1,1,1, %U A132181 5438578786,1,32631472722,1,2,1,391577672676,1,1,2,1,1566310690708,1,1 %N A132181 a(n)=smallest positive integer such that product{k=1 to n}(1+1/a(k)) has a prime numerator. %H A132181 Owen Whitby, Table of n, a(n) for n = 1..200 %H A132181 Leroy Quet, Home Page (listed in lieu of email address) %F A132181 Comments from Owen Whitby (whitbyo(AT)acm.org), May 07 2008 (Start): Successive terms a(.) can be calculated using the following recurrences for the numerator n(.) and denominator d(.) of the product. %F A132181 a(1)=1; n(1)=1, d(1)=1 ==> a(2)=1, n(2)=2, d(2)=1 ( to start things off ); %F A132181 n(i)=2, d(i)= odd ==> a(i+1)=q-1, n(i+1)=q, d(i+1)=d(i)(q-1)/2 where q is least odd prime not dividing d(i); %F A132181 n(i)=odd prime, d(i)=1 ==> a(i+1)=c*n(i), n(i+1)=c*n(i)+1, d(i+1)=c where c is least even integer such that c*n(i)+1 is prime; %F A132181 n(i)=odd prime, d(i)=even ==> a(i+1)=1, n(i+1)=n(i), d(i+1)=d(i)/2; %F A132181 n(i)=odd prime, d(i)= odd>=3 ==> a(i+1)=p-1, n(i+1)=n(i), d(i+1)=d(i)(p-1)/ p where p is least prime divisor of d(i). (End) %Y A132181 Sequence in context: A109530 A111519 A008855 this_sequence A027642 A117214 A134301 %Y A132181 Adjacent sequences: A132178 A132179 A132180 this_sequence A132182 A132183 A132184 %K A132181 nonn %O A132181 1,2 %A A132181 Leroy Quet Nov 04 2007 %E A132181 a(10) to a(59) and list of 200 terms added by Owen Whitby (whitbyo(AT)acm.org), May 07 2008 Search completed in 0.001 seconds