Search: id:A133771 Results 1-1 of 1 results found. %I A133771 %S A133771 2,1,1,2,4,1,3,2,3,1,4,4,3,3,2,6,1,5,4,5,3,4,4,3,3,2,3,1,6,6,5,5,4,6,3, %T A133771 5,4,5,3,4,4,3,3,2,8,1,7,6,7,5,6,6,5,5,4,5,3,6,6,5,5,4,6,3,5,4,5,3,4,4, %U A133771 3,3,2,3,1,8,8,7,7,6,8,5,7,6,7,5,6,6,5,5,4,8,3,7,6,7,5,6,6,5,5,4,5,3,6 %N A133771 Number of runs (of equal bits) in the maximal Lucas binary (A130311) representation of n. %D A133771 Zeckendorf, E., Representation des nombres naturels par une somme des nombres de Fibonacci ou de nombres de Lucas, Bull. Soc. Roy. Sci. Liege 41, 179-182, 1972. %H A133771 Casey Mongoven, Table of n, a(n) for n = 1..199 %H A133771 Ron Knott, Using Powers of Phi to represent Integers. %e A133771 A130311(19)=101110 because 11+4+3+1=19 (a sum of Lucas numbers); this representation has four runs: 1,0,111,0. So a(19)=4. %Y A133771 Cf. A133770, A130311. %Y A133771 Sequence in context: A056061 A029265 A103648 this_sequence A127309 A097853 A160266 %Y A133771 Adjacent sequences: A133768 A133769 A133770 this_sequence A133772 A133773 A133774 %K A133771 nonn %O A133771 1,1 %A A133771 Casey Mongoven (cm(AT)caseymongoven.com), Sep 23 2007; corrected Mar 23 2008 Search completed in 0.001 seconds