|
Search: id:A135238
|
|
|
| A135238 |
|
Numbers n such that phi(sigma(n))=reversal(n). |
|
+0 2
|
| |
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
If both numbers 10^m-3 & 5*10^(m-1)-1 are primes and n=3*(10^m-3) then phi(sigma(n))=reversal(n), namely n is in the sequence (the proof is easy). Conjecture: n=2991 is the only such term of the sequence. there is no further term up to 35*10^7.
|
|
EXAMPLE
|
phi(sigma(880374))=phi(1920960)=473088=reversal(880374), so 880374 is in the sequence.
|
|
MATHEMATICA
|
reversal[n_]:=FromDigits[Reverse[IntegerDigits[n]]]; Do[If[EulerPhi[DivisorSigma[1, n]]==reversal[n], Print[n]], {n, 350000000}]
|
|
CROSSREFS
|
Cf. A071525.
Sequence in context: A027733 A054874 A057841 this_sequence A133376 A160814 A038582
Adjacent sequences: A135235 A135236 A135237 this_sequence A135239 A135240 A135241
|
|
KEYWORD
|
base,more,nonn
|
|
AUTHOR
|
Farideh Firoozbakht (mymontain(AT)yahoo.com), Dec 26 2007
|
|
|
Search completed in 0.002 seconds
|