Search: id:A136565 Results 1-1 of 1 results found. %I A136565 %S A136565 0,1,1,2,1,1,1,3,2,1,1,3,1,1,1,4,1,3,1,3,1,1,1,4,2,1,3,3,1,1,1,5,1,1,1, %T A136565 2,1,1,1,4,1,1,1,3,3,1,1,5,2,3,1,3,1,4,1,4,1,1,1,3,1,1,3,6,1,1,1,3,1,1, %U A136565 1,5,1,1,3,3,1,1,1,5,4,1,1,3,1,1,1,4,1,3,1,3,1,1,1,6,1,3,3,2,1,1,1,4,1 %N A136565 a(n) = sum of the distinct values making up the exponents in the prime-factorization of n. %H A136565 Diana Mecum, Table of n, a(n) for n = 1..1000 %H A136565 Leroy Quet, Home Page (listed in lieu of email address) %e A136565 120 = 2^3 * 3^1 * 5^1. The exponents of the prime factorization are therefore 3,1,1. The distinct values which equal these exponents are 1 and 3. So a(120) = 1+3 = 4. %Y A136565 Cf. A071625, A136566, A136568. %Y A136565 Sequence in context: A000688 A038538 A088529 this_sequence A086291 A016442 A076360 %Y A136565 Adjacent sequences: A136562 A136563 A136564 this_sequence A136566 A136567 A136568 %K A136565 nonn %O A136565 1,4 %A A136565 Leroy Quet, Jan 07 2008 %E A136565 More terms from Diana Mecum (diana.mecum(AT)gmail.com), Jul 17 2008 Search completed in 0.001 seconds