Search: id:A136615 Results 1-1 of 1 results found. %I A136615 %S A136615 1,2,0,0,0,16,16,16,112,112,112,912,912,912,7280,7280,7280,58256,58256, %T A136615 58256,466032,466032,466032,3728272,3728272,3728272,29826160,29826160, %U A136615 29826160,238609296,238609296,238609296,1908874352,1908874352 %N A136615 Fold-switch-fold sequence defined by McFarlane and Withers for m=3: Let A(n) = If[Mod[A(n - 1), 2] == 0, A(n - 1)/2, (m - A(n - 1))2]; a(n)= If[ Mod[A(n - 1), 2] == 0, a(n - 1)/2, (Pi - a(n - 1))/2]. %D A136615 Cayanne McFarlane and Wm. Douglas Withers; Dynamical Systems and Irrational Angle Construction by Paper-Folding, American Mathematical Monthly, Volume 115, Number 4, 2008, page 356; http://www.maa.org/pubs/monthly_apr08_toc.html. %F A136615 m=3,A(0)=1;a(1)=(m-1)/2; A(n) = If[Mod[A(n - 1), 2] == 0, A(n - 1)/2, (m - A(n - 1))2]; a(0) = Pi; a(1) = Pi; a(n)= If[ Mod[A(n - 1), 2] == 0, a(n - 1)/2, (Pi - a(n - 1))/2]; output=2^n*a(n)/Pi %t A136615 Clear[A, m, n] m = 3; A[0] = 1; A[1] = (m - 1)/2; A[n_] := A[n] = If[Mod[A[n - 1], 2] == 0, A[n - 1]/2, (m - A[n - 1])2]; a[0] = Pi; a[1] = Pi; a[n_] := a[n] = If[ Mod[A[n - 1], 2] == 0, a[n - 1]/2, (Pi - a[n - 1])/2]; Table[2^n*a[n]/Pi, {n, 0, 50}] %Y A136615 Sequence in context: A158801 A107491 A063698 this_sequence A029696 A118887 A057383 %Y A136615 Adjacent sequences: A136612 A136613 A136614 this_sequence A136616 A136617 A136618 %K A136615 nonn %O A136615 1,2 %A A136615 Roger L. Bagula (rlbagulatftn(AT)yahoo.com), Mar 31 2008 Search completed in 0.001 seconds