Search: id:A140449
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%I A140449
%S A140449 3,5,6,10,12,15,18,20,27,30,36,40,42,45,48,54,60,63,70,72,77,80,88,90,
%T A140449 100,102,105,108,110,120,130,135,138,140,150,153,160,165,170,176,180,
%U A140449 187,192,195,198,204,221,225,228,230,238,240,242,252,259,264,270,272
%N A140449 a(n) = the multiple of A142972(n) such that the nth prime <= a(n) <= 
               the (n+1)th prime.
%C A140449 There is always only one multiple of A142972(n) that is between the nth 
               prime and the (n+1)th prime.
%H A140449 Leroy Quet, <a href="http://www.prism-of-spirals.net/">Home Page</a> 
               (listed in lieu of email address)
%e A140449 The 15th prime is 47 and the 16th prime is 53. So we will examine the 
               integers 47,48,49,50,51,52,53. Now, 1 divides each of these integers. 
               2 divides 48,50,52. 3 divides 48 and 51. 4 divides 48 and 52. 5 divides 
               50. 6 divides 48. 7 divides 49. 8 divides 48. But 9 doesn't divide 
               any integer in the span of consecutive integers 47 to 53. So 8 is 
               the largest integer m such that 1,2,3,4,...m each divide at least 
               one integer in the span 47 to 53. 48 is the multiple of 8 among the 
               integers in the span. So a(15) = 48.
%Y A140449 Cf. A142972.
%Y A140449 Sequence in context: A028927 A099190 A122772 this_sequence A115823 A112926 
               A027627
%Y A140449 Adjacent sequences: A140446 A140447 A140448 this_sequence A140450 A140451 
               A140452
%K A140449 nonn
%O A140449 1,1
%A A140449 Leroy Quet Jul 21 2008
%E A140449 Extended by Ray Chandler (rayjchandler(AT)sbcglobal.net), Jun 21 2009

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