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Search: id:A140724
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| A140724 |
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Period 10: 1, 5, 9, 7, 7, 9, 5, 1, 3, 3 repeated. |
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+0
2
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| 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7, 9, 5, 1, 3, 3, 1, 5, 9, 7, 7
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OFFSET
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0,2
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COMMENT
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The last digit of A108981(n).
Also the continued fraction of (290003+sqrt(240183699293))/652402.
Also the decimal expansion of 13073/81819.
The period contains each of the the 5 odd digits twice.
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FORMULA
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a(n)+a(n+5) = 10 = A010692(n).
a(n) = a(n+10) .
a(10*k+9+i) = a(10*k+18-i) (palindromic).
a(n) = 2*a(n-1)-2*a(n-2)+2*a(n-3)-2*a(n-4)+a(n-5). G.f.: -(1+3*x+x^2-3*x^3+3*x^4)/ ((x-1) * (x^4-x^3+x^2-x+1)).
a(n)=(1/45)*{14*(n mod 10)+5*[(n+1) mod 10]-4*[(n+2) mod 10]+23*[(n+3) mod 10]+23*[(n+4) mod 10]-4*[(n+5) mod 10]+5*[(n+6) mod 10]+14*[(n+7) mod 10]-13*[(n+8) mod 10]-13*[(n+9) mod 10]}, with n>=0 - Paolo P. Lava (ppl(AT)spl.at), Jul 14 2008
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CROSSREFS
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Sequence in context: A118309 A100106 A125650 this_sequence A086055 A077125 A160050
Adjacent sequences: A140721 A140722 A140723 this_sequence A140725 A140726 A140727
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KEYWORD
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nonn,easy
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AUTHOR
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Paul Curtz (bpcrtz(AT)free.fr), Jul 12 2008
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EXTENSIONS
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Edited by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Sep 07 2009
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