%I A141837
%S A141837 13,31,133,120332323
%N A141837 a(n) = first term that can be reduced in n steps via repeated interpretation
of a(n) as a base b+1 number where b is the largest digit of a(n),
such that b is always 3 so that each interpretation is base 4. Terms
already fully reduced (i.e. single digits) are excluded.
%C A141837 It is possible to compute additional terms by taking the last term, treating
it as base-10 and converting to base-4. This will necessarily create
a term which can converted back to base 10 yielding the previous
term in the sequence which will itself yield N further terms. But
there is no guarantee (except in base 2) that the term so derived
will be the first term to produce a sequence of N+1 terms. There
could be another, smaller, term which satisfies that requirement
but which uses different terms. Pushing the last term of this sequence
yields 13023002000203 as a possible next term.
%e A141837 a(3) = 133 because 133 is the first number that can produce a sequence
of three terms by repeated interpetation as a base 4 number: [133]
(base-4) --> [31] (base-4) --> [13] (base-4) --> [7]. Since 7 cannot
be interpretted as a base 4 number, the sequence terminates with
13. a(1) = 13 because 13 is the first number that can be reduced
once, yielding no further terms interprettable as base 4.
%Y A141837 Cf. A091049, A141836, A141838, A141839, A141840, A141841, A141842.
%Y A141837 Sequence in context: A043226 A044006 A007628 this_sequence A104151 A023304
A159670
%Y A141837 Adjacent sequences: A141834 A141835 A141836 this_sequence A141838 A141839
A141840
%K A141837 base,more,nonn
%O A141837 1,1
%A A141837 Chuck Seggelin (seqfan(AT)plastereddragon.com), Jul 10 2008
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