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Search: id:A144691
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| A144691 |
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a(n) = Limit_{m->infinity} [x^(2^m+n)] B(x)^(n+1)/(n+1) for n>=0, where B(x) = Sum_{k>=0} x^(2^k); thus a(n) = A144690(n)/(n+1). |
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| 1, 1, 2, 4, 26, 106, 816, 4292, 90162, 715138, 10275886, 87498566, 1944309280, 20988667064, 351769697800, 3865796198136
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