1,1

General formula for a(n+1)=a(n)^2+2*a(n)-2 and a(1)=k+1 is a(n)=Floor[((k + Sqrt[k^2 + 4])/2)^(2^((n+1) - 1))

Essentially the same as A110407. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Mar 18 2009]

aa = {}; k = 3; Do[AppendTo[aa, k]; k = k^2 + 2 k - 2, {n, 1, 10}]; aa

or

k = 2; Table[Floor[((k + Sqrt[k^2 + 4])/2)^(2^(n - 1))], {n, 2, 7}] (*Artur Jasinski*)

A145502-A145511

Sequence in context: A117808 A002065 A087601 this_sequence A112093 A085010 A165903

Adjacent sequences: A145500 A145501 A145502 this_sequence A145504 A145505 A145506

nonn

Artur Jasinski (grafix(AT)csl.pl), Oct 11 2008