Search: id:A146750 Results 1-1 of 1 results found. %I A146750 %S A146750 60,292,292,1176,2396,1176,4272,15584,15584,4272,14580,88178,156120, %T A146750 88178,14580,47804,455108,1310228,1310228,455108,47804 %N A146750 Coefficients pf the Pascal sequence minus the Eulerian numbers with first and last columns subtracted: f(n)=2^n - 2n; q(x,n)= = (1 - x)^(n + 1)*PolyLog[ -n, x]; p(x,n) = ((q(x, n)/x - (x + 1)^(n - 1))/x - f[n] - f[n]*x^(n - 3))/x. %C A146750 Row sums are:{60, 584, 4748, 39712, 361636, 3626280}. First row elements/ column are: {60, 292, 1176, 4272, 14580, 47804}. %F A146750 f(n)=2^n - 2n; q(x,n)= = (1 - x)^(n + 1)*PolyLog[ -n, x]; p(x,n) = ((q(x, n)/x - (x + 1)^(n - 1))/x - f[n] - f[n]*x^(n - 3))/x; t(n,m)=Coefficients(p(x, n)). %e A146750 {2}, {8, 8}, {22, 60, 22}, {52, 292, 292, 52}, {114, 1176, 2396, 1176, 114}, {240, 4272, 15584, 15584, 4272, 240}, {494, 14580, 88178, 156120, 88178, 14580, 494}, {1004, 47804, 455108, 1310228, 1310228, 455108, 47804, 1004} %t A146750 f[n_] = 2^n - 2n; q[x_, n_] = (1 - x)^(n + 1)*PolyLog[ -n, x]; p[x_, n_] = ((q[x, n]/x - (x + 1)^(n - 1))/x - f[n] - f[n]*x^(n - 3))/x Table[CoefficientList[FullSimplify[ExpandAll[p[x, n]]], x], {n, 5, 10}] Flatten[%] %Y A146750 A005803 %Y A146750 Sequence in context: A100154 A100148 A100151 this_sequence A063497 A096363 A033591 %Y A146750 Adjacent sequences: A146747 A146748 A146749 this_sequence A146751 A146752 A146753 %K A146750 nonn %O A146750 5,1 %A A146750 Roger L. Bagula (rlbagulatftn(AT)yahoo.com), Nov 01 2008 Search completed in 0.001 seconds