Search: id:A154811
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%I A154811
%S A154811 1,2,5,4,7,8,8,7,4,5,2,1,1,2,5,4,7,8,8,7,4,5,2,1,1,2,5,4,7,8,8,7,4,5,2,
%T A154811 1,1,2,5,4,7,8,8,7,4,5,2,1,1,2,5,4,7,8,8,7,4,5,2,1,1,2,5,4,7,8,8,7,4,5,
%U A154811 2,1
%N A154811 Fibonacci(2n+1) mod 9.
%C A154811 Periodic with period length 12. The period 1, 2, 5, 4, 7, 8, 8, 7, 4, 
               5, 2, 1 is the palindrom of the one in A153990.
%C A154811 There is some connection to A014217 using the formula with phi=(1+sqrt(5))/
               2 in A001519.
%C A154811 Terms of the simple continued fraction of 4343150/(sqrt(21657897254981)-1671809). 
               [From Paolo P. Lava (ppl(AT)spl.at), Feb 17 2009]
%F A154811 a(n)= A001519(n+1) mod 9 = A122367(n) mod 9 = |A099496(n)| mod 9.
%F A154811 a(n)=(1/132)*{9*(n mod 12)+20*[(n+1) mod 12]+42*[(n+2) mod 12]-2*[(n+3) 
               mod 12]+42*[(n+4) mod 12]+20*[(n+5) mod 12]+9*[(n+6) mod 12]-2*[(n+7) 
               mod 12]-24*[(n+8) mod 12]+20*[(n+9) mod 12]-24*[(n+10) mod 12]-2*[(n+11) 
               mod 12]}, with n>=0 [From Paolo P. Lava (ppl(AT)spl.at), Jan 16 2009]
%F A154811 a(n)=a(n-1)-a(n-6)+a(n-7). G.f.: -(1+x+3*x^2-x^3+3*x^4+x^5+x^6)/((x-1)*(x^2+1)*(x^4-x^2+1)). 
               [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 10 2009]
%Y A154811 Sequence in context: A085801 A023843 A153990 this_sequence A036237 A015948 
               A119733
%Y A154811 Adjacent sequences: A154808 A154809 A154810 this_sequence A154812 A154813 
               A154814
%K A154811 nonn,easy
%O A154811 0,2
%A A154811 Paul Curtz (bpcrtz(AT)free.fr), Jan 15 2009
%E A154811 Edited by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jan 23 2009
%E A154811 Corrected typo in A-number in first formula R. J. Mathar (mathar(AT)strw.leidenuniv.nl), 
               Feb 23 2009

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