Search: id:A158387 Results 1-1 of 1 results found. %I A158387 %S A158387 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1, %T A158387 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1, %U A158387 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 %V A158387 -1,1,1,-1,1,1,1,1,-1,1,1,1,1,1,1,-1,1,1,1,1,1,1,1,1,-1,1,1,1,1,1,1,1, 1, %W A158387 1,1,-1,1,1,1,1,1,1,1,1,1,1,1,1,-1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,-1,1,1, 1, %X A158387 1,1,1,1,1,1,1,1,1,1,1,1,1,-1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,-1 %N A158387 a(n) = sign of parity of number of divisors of n. %C A158387 a(n) = (-1)^tau(n) = (-1)^A000005. a(1) = -1, a(p) = 1, a(pq) = 1, a(pq...z) = 1, a(p^k) = (-1)^(k+1), for p = primes (A000040), pq = product of two distinct primes (A006881), pq...z = product of k (k > 2) distinct primes p, q, ..., z (A120944), p^k = prime powers (A000961(n) for n > 1), k = natural numbers (A000027). %e A158387 a(12) = (-1)^6 = 1. %Y A158387 Cf.: A000005, A000040, A006881, A120944, A000961, A000027. %Y A158387 Sequence in context: A157895 A063747 A077008 this_sequence A087960 A164660 A114523 %Y A158387 Adjacent sequences: A158384 A158385 A158386 this_sequence A158388 A158389 A158390 %K A158387 sign %O A158387 1,1 %A A158387 Jaroslav Krizek (jaroslav.krizek(AT)atlas.cz), Mar 17 2009 Search completed in 0.001 seconds