Search: id:A160691 Results 1-1 of 1 results found. %I A160691 %S A160691 1,2,2,2,4,2,2,4,2,2,4,2,2,4,2,4,2,4,4,4,2,4,4,4,2,4,6,4,6,2,4,4,4,4,4, %T A160691 4,4,4,4,4,4,2,2,4,4,4,2,4,4,2,4,2,4,4,4,2,2,4,4,2,4,4,4,2,4,2,4,4,2,4, %U A160691 4,4,4,4,4,4,4,4,4,4,4,2,2,4,2,4,4,2,4,4,4,4,4,4,4,4,2,4,2,4,4,2,4,4,2 %N A160691 a(n) = the number of divisors of A160689(n) = the number of divisors of A160690(n). %C A160691 Contribution from Farideh Firoozbakht (mymontain(AT)yahoo.com), May 28 2009: (Start) %C A160691 For the first 200000 natural numbers n, a(n) is in the set {1,2,4,6,8, 12} %C A160691 and in fact we have: %C A160691 For one number n, A160691(n)=1. %C A160691 For 13 numbers n, A160691(n)=12 (see the sequence A158963). %C A160691 For 4785 numbers n, A160691(n)=6. %C A160691 For 6706 numbers n, A160691(n)=8. %C A160691 For 26790 numbers n, A160691(n)=2. %C A160691 For 161705 numbers n, A160691(n)=4. %C A160691 Also n=2 is the only number n (less than 200000) that a(n)=a(n+1)=a(n+2)=2. %C A160691 and for the 53 consecutive numbers 64833, 64834, ... , 64885 we have a(n)=4. (End) %t A160691 Contribution from Farideh Firoozbakht (mymontain(AT)yahoo.com), May 28 2009: (Start) %t A160691 c[1]=1;c[n_]:=c[n]=(s=Sum[c[k],{k,n-1}];For[m=1,DivisorSigma[0,m]!= %t A160691 DivisorSigma[0,s+m],m++ ];m);a[n_]:=a[n]=DivisorSigma[0,c[n]]; %t A160691 Table[a[n],{n,105}] (End) %Y A160691 A160689, A160690 %Y A160691 Cf. A158963, A158964. [From Farideh Firoozbakht (mymontain(AT)yahoo.com), May 28 2009] %Y A160691 Sequence in context: A075016 A102445 A027389 this_sequence A049716 A066671 A159802 %Y A160691 Adjacent sequences: A160688 A160689 A160690 this_sequence A160692 A160693 A160694 %K A160691 nonn %O A160691 1,2 %A A160691 Leroy Quet (q1qq2qqq3qqqq(AT)yahoo.com), May 24 2009 %E A160691 More terms from Farideh Firoozbakht (mymontain(AT)yahoo.com), May 28 2009 Search completed in 0.001 seconds