Logo

Greetings from The On-Line Encyclopedia of Integer Sequences!

Hints

Search: id:A000073
Displaying 1-1 of 1 results found. page 1
     Format: long | short | internal | text      Sort: relevance | references | number      Highlight: on | off
A000073 Tribonacci numbers: a(n) = a(n-1) + a(n-2) + a(n-3).
(Formerly M1074 N0406)
+0
148
0, 0, 1, 1, 2, 4, 7, 13, 24, 44, 81, 149, 274, 504, 927, 1705, 3136, 5768, 10609, 19513, 35890, 66012, 121415, 223317, 410744, 755476, 1389537, 2555757, 4700770, 8646064, 15902591, 29249425, 53798080, 98950096, 181997601, 334745777 (list; graph; listen)
OFFSET

0,5

COMMENT

Also (for n>2) number of ways writing 2^(n-2) as a product of decimal digits of some other number which has no digits equal to 1; e.g. n=8: 2^n=256, solutions = {488, ..., 8822, ..84222, .., 822222, ...4222222, 22222222}, their number is 81; so a(n+2)=A067374(2^n) - Labos E. (labos(AT)ana.sote.hu), Jan 28 2002.

Also (for n>1) number of ordered trees with n+1 edges and having all leaves at level three. Example: a(4)=2 because we have two ordered trees with 5 edges and having all leaves at level three: (i) one edge emanating from the root, at the end of which two paths of length two are hanging and (ii) one path of length two emanating from the root, at the end of which three edges are hanging. - Emeric Deutsch (deutsch(AT)duke.poly.edu), Jan 03 2004

a(n)=number of compositions of n-2 with no part greater than 3. Example: a(5)=4 because we have 1+1+1=1+2=2+1=3. - Emeric Deutsch (deutsch(AT)duke.poly.edu), Mar 10 2004

Let A=[0,0,1;1,1,1;0,1,0]. A000073(n) corresponds to both the (1,2) and (3,1) positions in A^n. - Paul Barry (pbarry(AT)wit.ie), Oct 15 2004

Number of permutations satisfying -k<=p(i)-i<=r, i=1..n-2, with k=1, r=2. - Vladimir Baltic (baltic(AT)galeb.etf.bg.ac.yu), Jan 17 2005

Number of binary sequences of length n-3 that have no three consecutive 0's. Example: a(7)=13 because among the 16 binary sequences of length 4 only 0000, 0001, and 1000 have 3 consecutive 0's. - Emeric Deutsch (deutsch(AT)duke.poly.edu), Apr 27 2006

Let C = the tribonacci constant, 1.83928675...; then C^n = a(n)*(1/C) + a(n+1)*(1/C + 1/C^2) + a(n+2)*(1/C + 1/C^2 + 1/C^3). Example: C^4 = 11.444...= 2*(1/C) + 4*(1/C + 1/C^2) + 7*(1/C + 1/C^2 + 1/C^3). - Gary W. Adamson (qntmpkt(AT)yahoo.com), Nov 05 2006

a(n) =(j*c^n)+(k*r1^n)+(l*r2^n) where c is the Tribonacci constant (c=1,8392867552), real root of x^3-x^2-x-1=0 and r1 and r2 the two others roots (complex) r1=m+pI r2=m-pI where m= (1-c)/2 (m=-0,4196433776) and p = ((3*c-5)*(c+1)/4)^(1/2) (p=0,6062907292) and where j= 1/((c-m)^2+p^2) (=0,1828035330) k = a+bI and l =a-bI where a= -j/2 (a=-0,0914017665) and b=(c-m)/(2*p*((c-m)^2+p^2)(b=0,3405465308) - Philippe LALLOUET (philip.lallouet(AT)wanadoo.fr), Jun 23 2007

REFERENCES

S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures}, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.

A. T. Benjamin and J. J. Quinn, Proofs that really count: the art of combinatorial proof, M.A.A. 2003, p. 47, ex. 4.

M. S. El Naschie, Statistical geometry of a Cantor discretum and semiconductors, Computers Math. Applic., 29 (No, 12, 1995), 103-110.

Nathaniel D. Emerson, A Family of Meta-Fibonacci Sequences Defined by Variable-Order Recursions, Journal of Integer Sequences, Vol. 9 (2006), Article 06.1.8.

M. Feinberg, Fibonacci-Tribonacci, Fib. Quart. 1(#3) (1963), 71-74.

M. Feinberg, New slants, Fib. Quart., 2 (1964), 223-227.

S. R. Finch, Mathematical Constants, Cambridge, 2003, Section 1.2.2.

M. D. Hirschhorn, Coupled third-order recurrences, Fib. Quart., 44 (2006), 26-31.

O. Martin, A. M. Odlyzko and S. Wolfram, Algebraic properties of cellular automata, Comm. Math. Physics, 93 (1984), pp. 219-258, Reprinted in Theory and Applications of Cellular Automata, S. Wolfram, Ed., World Scientific, 1986, pp. 51-90, and in Cellular Automata and Complexity: Collected Papers of Stephen Wolfram, Addison-Wesley, 1994, pp. 71-113. See Eq. 5.5b.

Tony D. Noe and Jonathan Vos Post, Primes in Fibonacci n-step and Lucas n-step Sequences, Journal of Integer Sequences, Vol. 8 (2005), Article 05.4.4.

J. Riordan, An Introduction to Combinatorial Analysis, Princeton University Press, Princeton, NJ, 1978.

M. E. Waddill and L. Sacks, Another generalized Fibonacci sequence, Fib. Quart., 5 (1967), 209-222.

LINKS

T. D. Noe, Table of n, a(n) for n = 0..200

Joerg Arndt, Fxtbook

S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures}, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.

S. Plouffe, 1031 Generating Functions and Conjectures, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.

P. J. Cameron, Sequences realized by oligomorphic permutation groups, J. Integ. Seqs. Vol. 3 (2000), #00.1.5.

INRIA Algorithms Project, Encyclopedia of Combinatorial Structures 10

S. Kak, The Golden Mean and the Physics of Aesthetics

T. Mansour, Permutations avoiding a set of patterns T \subseteq S_3 and a pattern \tau \in S_4

Eric Weisstein's World of Mathematics, Link to a section of The World of Mathematics.

Eric Weisstein's World of Mathematics, Link to a section of The World of Mathematics.

FORMULA

G.f.: x^2/(1 - x - x^2 - x^3)

a(n+1)/a(n) -> A058265.

a(n) = center term in M^n * [1 0 0] where M = the 3X3 matrix [0 1 0 / 0 0 1 / 1 1 1]. (M^n * [1 0 0] = [a(n-1) a(n) a(n+1)]). a(n)/a(n-1) tends to the tribonacci constant, 1.839286755...an eigenvalue of M and a root of x^3 - x^2 - x - 1 = 0. - Gary W. Adamson (qntmpkt(AT)yahoo.com), Dec 17 2004

a(n+2)=sum{k=0..n, T(n-k, k)}, T(n, k) = trinomial coefficients (A027907); - Paul Barry (pbarry(AT)wit.ie), Feb 15 2005

A001590(n)=a(n+1)-a(n); A001590(n)=a(n-1)+a(n-2) for n>1; a(n)=(A000213(n+1)-A000213(n))/2; A000213(n-1)=a(n+2)-a(n) for n>0. - Reinhard Zumkeller (reinhard.zumkeller(AT)lhsystems.com), May 22 2006

MAPLE

A000073:=-z/(-1+z+z**2+z**3); [Conjectured by S. Plouffe in his 1992 dissertation.]

MATHEMATICA

CoefficientList[Series[x^2/(1 - x - x^2 - x^3), {x, 0, 50}], x]

PROGRAM

(PARI) {a(n) = polcoeff( if( n<0, x / ( 1 + x + x^2 - x^3), x^2 / ( 1 - x - x^2 - x^3) ) + x*O(x^abs(n)), abs(n))} /* Michael Somos Sep 03 2007 */

CROSSREFS

A057597 is this sequence run backwards: A057597(n) = a(1-n).

Cf. A063401, A001590, A008937, A089068, A027084.

Cf. A062544, A077902, A054668, A027083, A000213, A027024.

Cf. A118390.

Row 3 of arrays A048887 and A092921 (k-generalized Fibonacci numbers).

Adjacent sequences: A000070 A000071 A000072 this_sequence A000074 A000075 A000076

Sequence in context: A107281 A006744 A054175 this_sequence A005318 A102111 A059633

KEYWORD

nonn,easy,nice

AUTHOR

njas

EXTENSIONS

More terms from Larry Reeves (larryr(AT)acm.org), Jul 31 2000

page 1

Search completed in 0.004 seconds

Lookup | Welcome | Find friends | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Transforms | Puzzles | Hot | Classics
More pages | Superseeker | Maintained by N. J. A. Sloane (njas@research.att.com)

Last modified May 11 10:28 EDT 2008. Contains 139662 sequences.


AT&T Labs Research