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Search: id:A000330
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| A000330 |
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Square pyramidal numbers: 0^2+1^2+2^2+...+n^2 = n(n+1)(2n+1)/6. (Formerly M3844 N1574)
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+0 137
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| 0, 1, 5, 14, 30, 55, 91, 140, 204, 285, 385, 506, 650, 819, 1015, 1240, 1496, 1785, 2109, 2470, 2870, 3311, 3795, 4324, 4900, 5525, 6201, 6930, 7714, 8555, 9455, 10416, 11440, 12529, 13685, 14910, 16206, 17575, 19019, 20540, 22140, 23821, 25585, 27434, 29370
(list; graph; listen)
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OFFSET
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0,3
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COMMENT
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The sequence contains exactly one square greater than 1, namely 4900 (according to Gardner). - Jud McCranie (j.mccranie(AT)comcast.net), Mar 19 2001, Mar 22 2007
Number of rhombi in an n X n rhombus. - Matti De Craene (Matti.DeCraene(AT)rug.ac.be), May 14 2000
Number of acute triangles made from the vertices of a regular n-polygon when n is odd (cf. A007290). - Sen-Peng You (giawgwan(AT)single.url.com.tw), Apr 05 2001
Gives number of squares formed from an n X n square. In a 1 X 1 square, one is formed. In a 2 X 2 square, five squares are formed. In a 3 X 3 square, 14 squares are formed, and so on. - Kristie Smith (kristie10spud(AT)hotmail.com), Apr 16 2002
a(n-1)=B_3(n)/3 where B_3(x)=x(x-1)(x-1/2) is the third Bernoulli polynomial. - Michael Somos Mar 13 2004
Number of permutations avoiding 13-2 that contain the pattern 32-1 exactly once.
Since 3*r = (r+1)+r+(r-1) = T(r+1)-T(r-2), where T(r) = r-th triangular number r*(r+1)/2, we have 3*r^2 = r*{T(r+1)-T(r-2)} = f(r+1)-f(r-1)......(i), where f(r) = (r-1)*T(r) = (r+1)*T(r-1). Summing over n, R.H.S. of relation (i) telescopes to f(n+1)+f(n) = T(n)*{(n+2)+(n-1)}, whence result sum_(1, n)r^2 = n*(n+1)*(2*n+1)/6 immediately follows. - Lekraj Beedassy (blekraj(AT)yahoo.com), Aug 06 2004
Also as a(n)=(1/6)*(2*n^3+3*n^2+n), n>0: structured trigonal diamond numbers (vertex structure 5) (Cf. A006003 = alternate vertex; A000447 = structured diamonds; A100145 for more on structured numbers). - James A. Record (james.record(AT)gmail.com), Nov. 7, 2004.
Number of triples of integers from {1,2,...,n} whose last component is greater than or equal to the others.
Kekule numbers for certain benzenoids. - Emeric Deutsch (deutsch(AT)duke.poly.edu), Jun 12 2005
Sum of the first n squares, or square pyramidal numbers. - Cino Hilliard (hillcino368(AT)hotmail.com), Jun 18 2007
Maximal number of cubes of side 1 in a right pyramid with a square base of side n and height n - Pasquale CUTOLO (p.cutolo(AT)inwind.it), Jul 09 2007
If a 2-set Y and an (n-2)-set Z are disjoint subsets of an n-set X then a(n-3) is the number of 4-subsets of X intersecting both Y and Z. - Milan R. Janjic (agnus(AT)blic.net), Sep 19 2007
We also have the identity (1+(1+4)+(1+4+9)+..+(1+4+9+16+ .. + n^2)=n(n+1)(n+2)[n+(n+1)+(n+2)]/36; .. and in general the k-fold nested sum of squares can be expressed as n(n+1)...(n+k)[n+(n+1)+...+(n+k)]/((k+2)!(k+1)/2 ) - Alexander R. Povolotsky (pevnev(AT)juno.com), Nov 21 2007
The terms of this sequence are coefficients of the Engel expansion of the following converging sum: 1/(1^2) + (1/1^2)*(1/(1^2+2^2)) + (1/1^2)*(1/(1^2+2^2))*(1/(1^2+2^2+3^2)) + .. - Alexander R. Povolotsky (pevnev(AT)juno.com), Dec 10 2007
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REFERENCES
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S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures}, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.
M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards Applied Math. Series 55, 1964 (and various reprintings), p. 813.
A. H. Beiler, Recreations in the Theory of Numbers, Dover, NY, 1964, p. 194.
A. T. Benjamin and J. J. Quinn, Proofs that really count: the art of combinatorial proof, M.A.A. 2003, id. 215,223.
L. Comtet, Advanced Combinatorics, Reidel, 1974, p. 122, see #19 (3(1)), I(n); p. 155.
H. S. M. Coxeter, Polyhedral numbers, pp. 25-35 of R. S. Cohen, J. J. Stachel and M. W. Wartofsky, eds., For Dirk Struik: Scientific, historical and political essays in honor of Dirk J. Struik, Reidel, Dordrecht, 1974.
S. J. Cyvin and I. Gutman, Kekule structures in benzenoid hydrocarbons, Lecture Notes in Chemistry, No. 46, Springer, New York, 1988 (p.165).
L. E. Dickson, History of the Theory of Numbers. Carnegie Institute Public. 256, Washington, DC, Vol. 1, 1919; Vol. 2, 1920; Vol. 3, 1923, see vol. 2, p. 2.
M. Gardner, Fractal Music, Hypercards, and More, Freeman, NY, 1991, pg 293.
Manfred Goebel, Rewriting Techniques and Degree Bounds for Higher Order Symmetric Polynomials, Applicable Algebra in Engineering, Communication and Computing (AAECC), Volume 9, Issue 6 (1999), 559-573.
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LINKS
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T. D. Noe, Table of n, a(n) for n = 0..1000
Milan Janjic, Two Enumerative Functions
M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards, Applied Math. Series 55, Tenth Printing, December 1972 [alternative scanned copy].
S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures}, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.
S. Plouffe, 1031 Generating Functions and Conjectures, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.
H. Bottomley, Illustration of initial terms
R. Jovanovic, First 2500 Pyramidal numbers
T. Mansour, Restricted permutations by patterns of type 2-1.
T. Sillke, Square Counting
Eric Weisstein's World of Mathematics, Link to a section of The World of Mathematics.
G. Xiao, Sigma Server, Operate on"n^2"
Index entries for "core" sequences
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FORMULA
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a(n)=binomial(2(n+1), 3)/4 - Paul Barry (pbarry(AT)wit.ie), Jul 19 2003
a(n)=[(n^4-(n-1)^4)-(n^2-(n-1)^2)]/12 - Xavier Acloque Oct 16 2003
a(n) = Sqrt[Sum[Sum[(i*j)^2, {i, 1, n}], {j, 1, n}]. a(n) = Sum[Sum[Sum[(i*j*k)^2, {i, 1, n}], {j, 1, n}], {k, 1, n}]^(1/3). - Alexander Adamchuk (alex(AT)kolmogorov.com), Oct 26 2004
a(n)=sum(i=1, n, i*(2*n-2*i+1)) - sum of squares gives 1+(1+3)+(1+3+5)+... - Jon Perry (perry(AT)globalnet.co.uk), Dec 08 2004
a(n+1) = A000217(n+1) + 2*A000292(n-1) - Creighton Dement (creighton.k.dement(AT)uni-oldenburg.de), Mar 10 2005
Sum_{ n>0} 1/a(n) = 6(3 - 4log(2)) and Sum_{ n>0} = (-1)^(n+1)*1/a(n) = 6(Pi - 3) . - Philippe DELEHAM (kolotoko(AT)wanadoo.fr), May 31 2005
Sum of two consecutive tetrahedral (or pyramidal) numbers A000292: C(n+3,3) = (n+1)(n+2)(n+3)/6: a(n) = A000292(n-1) + A000292(n-2). - Alexander Adamchuk (alex(AT)kolmogorov.com), May 17 2006
Euler transform of length 2 sequence [ 5, -1]. - Michael Somos Sep 04 2006
G.f.: x(1+x)/(1-x)^4. E.g.f.: (x+3/2*x^2+1/3*x^3)*exp(x).
a(n)=n(n+1)(2n+1)/6=binomial(n+2, 3)+binomial(n+1, 3)=-a(-1-n).
a(n) = a(n-1) + n^2 - Rolf Pleisch (r.pleisch(AT)gmx.ch), Jul 22 2007
a(n) = A132121(n,0). - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Aug 12 2007
Hankel transform of C(2n-3,n-1) is -a(n). - Paul Barry (pbarry(AT)wit.ie), Feb 12 2008
Convolution of A000290 with A000012 - Sergio Falcon (sfalcon(AT)dma.ulpgc.es), Feb 05 2008
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MAPLE
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A000330 := n->n*(n+1)*(2*n+1)/6;
a:=n->(1/6)*n*(n+1)*(2*n+1): seq(a(n), n=0..53); (Deutsch)
a:=n->sum ((j-n-1)^2, j=1..n): seq(a(n), n=0..44); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Dec 17 2006
a:=array(0...44): a[0]:=0: a[1]:=1:print(0, a[0]); print(1, a[1]); for i from 2 to 40 do a[i]:= a[i-1]+(i^2):print(i, a[i]); od: - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Mar 27 2007
A000330:=(1+z)/(z-1)**4; [Conjectured by S. Plouffe in his 1992 dissertation.]
with(combstruct):ZL:=[st, {st=Prod(left, right), left=Set(U, card=r), right=Set(U, card=r), U=Sequence(Z, card>=1)}, unlabeled]: subs(r=1, stack): seq(count(subs(r=2, ZL), size=m*2), m=1..45) ; - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jan 02 2008
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MATHEMATICA
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Table[Binomial[w+2, 3]+Binomial[w+1, 3], {w, 1, 30}]
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PROGRAM
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(PARI) a(n)=n*(n+1)*(2*n+1)/6
Floretion Algebra Multiplication Program, FAMP Code: 1vesforseq[ + .5'i + .5i' + .5'jk' + .5'kj' + e ], ForType: 1B, LoopType: tes (2nd iteration). (Dement)
(PARI) sumsq(n) = for(x=0, n, y=x*(x+1)*(2*x+1)/6; (print1(y", "))) - Cino Hilliard (hillcino368(AT)hotmail.com), Jun 18 2007
(PARI) a(n)=sum(m=1, n, sum(i=1, m, (2*i-1))) - Alexander R. Povolotsky (pevnev(AT)juno.com), Nov 04 2007
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CROSSREFS
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A006331(n)=2*A000330(n). Cf. A000217, A050446, A050447, A000537, A006003.
Cf. A000292, A033994, A132124, A132112, A050409.
Sums of 2 consecutive terms give A005900.
Column 0 of triangle A094414. Column 1 of triangle A008955. Right side of triangle A082652. Row 2 of array A103438.
Adjacent sequences: A000327 A000328 A000329 this_sequence A000331 A000332 A000333
Sequence in context: A096893 A074784 A109678 this_sequence A070129 A081861 A023652
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KEYWORD
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nonn,easy,core,nice
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AUTHOR
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njas
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