0,3

Consider the mapping f(a/b) = (a + 3b)/(a + b). Taking a = b = 1 to start with, and carrying out this mapping repeatedly on each new (reduced) rational number gives the following sequence 1/1,2/1,5/3,7/4,19/11,... converging to 3^(1/2). Sequence contains the numerators. - Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Mar 22 2003

In the Murthy comment if we take a=0, b=1 then the denominator of the reduced fraction is a(n+1). A083336(n)/a(n+1) converges to sqrt(3). - Mario Catalani (mario.catalani(AT)unito.it), Apr 26 2003

If signs are disregarded, all terms of A002316 appear to be elements of this sequence. - Creighton Dement (creighton.k.dement(AT)uni-oldenburg.de), Jun 11 2007

S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures}, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.

I. Niven and H. S. Zuckerman, An Introduction to the Theory of Numbers. 2nd ed., Wiley, NY, 1966, p. 181.

A. Tarn, Approximations to certain square roots and the series of numbers connected therewith, Mathematical Questions and Solutions from the Educational Times, 1 (1916), 8-12.

T. D. Noe, Table of n, a(n) for n = 0..200

S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures}, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.

S. Plouffe, 1031 Generating Functions and Conjectures, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.

Index entries for "core" sequences

G.f.: (1+x-2x^2+x^3)/(1-4x^2+x^4).

a(2n) = a(2n-1) + a(2n-2), a(2n+1) = 2a(2n) + a(2n-1), n>0.

a(2n)=(1/2)*((2+sqrt(3))^n+(2-sqrt(3))^n); a(2n)=A003500(n)/2; a(2n+1) = round( 1/(1+sqrt(3))*(2+sqrt(3))^n) - Benoit Cloitre (benoit7848c(AT)orange.fr), Dec 15 2002

1+1/(1+1/(2+1/(1+1/2)))=19/11 so a(5)=19.

Convergents are 1, 2, 5/3, 7/4, 19/11, 26/15, 71/41, 97/56, 265/153, 362/209, 989/571, 1351/780, 3691/2131, ... = A002531/A002530

A002531 := proc(n) option remember; if n=0 then 0 elif n=1 then 1 elif n=2 then 1 elif type(n, odd) then A002531(n-1)+A002531(n-2) else 2*A002531(n-1)+A002531(n-2) fi; end; [ seq(A002531(n), n=0..50) ];

with(numtheory): tp := cfrac (tan(Pi/3), 100): seq(nthnumer(tp, i), i=-1..32 ); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 07 2007

A002531:=(1+z-2*z**2+z**3)/(1-4*z**2+z**4); [Conjectured by S. Plouffe in his 1992 dissertation.]

Insert[Table[Numerator[FromContinuedFraction[ContinuedFraction[Sqrt[3], n]]], {n, 1, 40}], 1, 1] - Stefan Steinerberger (stefan.steinerberger(AT)gmail.com), Apr 01 2006

(PARI) a(n)=if(n<0, 0, contfracpnqn(vector(n, i, 1+(i>1)*(i%2)))[1, 1])

Bisections are A001075 and A001834.

Cf. A002530, A048788.

Cf. A002316.

Sequence in context: A045359 A042809 A108413 this_sequence A042449 A046115 A089443

Adjacent sequences: A002528 A002529 A002530 this_sequence A002532 A002533 A002534

nonn,frac,easy,core,nice

njas