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Search: id:A003434
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| A003434 |
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Number of iterations of phi(n) needed to reach 1.
(Formerly M0244)
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+0
20
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| 0, 1, 2, 2, 3, 2, 3, 3, 3, 3, 4, 3, 4, 3, 4, 4, 5, 3, 4, 4, 4, 4, 5, 4, 5, 4, 4, 4, 5, 4, 5, 5, 5, 5, 5, 4, 5, 4, 5, 5, 6, 4, 5, 5, 5, 5, 6, 5, 5, 5, 6, 5, 6, 4, 6, 5, 5, 5, 6, 5, 6, 5, 5, 6, 6, 5, 6, 6, 6, 5, 6, 5, 6, 5, 6, 5, 6, 5, 6, 6, 5, 6, 7, 5, 7, 5, 6, 6, 7, 5, 6, 6, 6, 6, 6, 6, 7, 5, 6, 6, 7, 6, 7, 6, 6
(list; graph; listen)
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OFFSET
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1,3
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REFERENCES
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S. Sivasankaranarayana Pillai, On a function associated with phi(n), Bull. Amer. Math. Soc., 35 (1929), 837-841.
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LINKS
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T. D. Noe, Table of n, a(n) for n = 1..10000
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FORMULA
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By the definition of a(n) we have for n >= 2 the recursion a(n) = a(Phi(n)) + 1. - Ahmed Fares (ahmedfares(AT)my-deja.com), Apr 20 2001
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EXAMPLE
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If n=164 the trajectory is {164,80,32,16,8,4,2,1}. Its length is 8, thus a(164)=7.
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MATHEMATICA
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f[n_] := Length[ NestWhileList[ EulerPhi, n, Unequal, 2]] - 2; Table[ f[n], {n, 1, 105} ]
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CROSSREFS
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Cf. A000010, A007755. Equals A049108 - 1.
Sequence in context: A136510 A080071 A019569 this_sequence A097849 A100678 A026834
Adjacent sequences: A003431 A003432 A003433 this_sequence A003435 A003436 A003437
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KEYWORD
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nonn,easy,nice
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AUTHOR
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njas
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