0,5

If we omit the first three terms of the sequence, a(n)/a(n-1) can be expressed as the continued fraction [a(n-2); a(n-1)]. - Eric Angelini (eric.angelini(AT)kntv.be), Feb 10 2005

This may be regarded as a multiplicative dual of the Fibonacci sequence A000045. Write Fibonacci's formula as F(0)=0, F(1)=1; F(n)=[F(n-1)+F(n-2)]*1 with n>1. Swap '+' and '*' and we have the present sequence! - B. Joshipura (bhushit(AT)yahoo.com), Aug 29 2007

B. Joshipura, My non-mathematician's posting

S. Kak, The Golden Mean and the Physics of Aesthetics

a(n) is asymptotic to c^(phi^n) where phi=(1+sqrt(5))/2 and c=1.1130579759029319... - Benoit Cloitre (benoit7848c(AT)orange.fr), Sep 26 2003

a[0] = a[1] = 0; a[n_] := a[n - 1]*a[n - 2] + 1; Table[ a[n], {n, 0, 15} ]

Sequence in context: A038159 A077210 A072214 this_sequence A134412 A005115 A113872

Adjacent sequences: A007657 A007658 A007659 this_sequence A007661 A007662 A007663

nonn,easy

njas, Robert G. Wilson v (rgwv(AT)rgwv.com)