15,2

a(n) = -A110555(n+1,15). - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jul 27 2005

Product of 15 consecutive numbers divided by 15! - Artur Jasinski (grafix(AT)csl.pl), Dec 02 2007

In this sequence there are no primes - Artur Jasinski (grafix(AT)csl.pl), Dec 02 2007

With a different offset, number of n-permutations (n>=15) of 2 objects: u,v, with repetition allowed, containing exactly (15) u's. Example: n=15, a(0)=1 because we have uuuuuuuuuuuuuuu n=16, a(1)=16 because we have uuuuuuuuuuuuuuuv, uuuuuuuuuuuuuuvu, uuuuuuuuuuuuuvuu, uuuuuuuuuuuuvuuu, uuuuuuuuuuuvuuuu, uuuuuuuuuuvuuuuu, uuuuuuuuuvuuuuuu, uuuuuuuuvuuuuuuu, uuuuuuuvuuuuuuuu, uuuuuuvuuuuuuuuu, uuuuuvuuuuuuuuuu, uuuuvuuuuuuuuuuu, uuuvuuuuuuuuuuuu, uuvuuuuuuuuuuuuu, uvuuuuuuuuuuuuuu, vuuuuuuuuuuuuuuu. [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Aug 06 2008]

With a different offset, number of n-permutations (n>=15) of 2 objects: u,v, with repetition allowed, containing exactly 15 u's. - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Aug 03 2008

Milan Janjic, Two Enumerative Functions

a(n)=n(n+1)(n+2)(n+3)(n+4)(n+5)(n+6)(n+7)(n+8)(n+9)(n+10)(n+11)(n+12)(n+13)(n+14)/15! - Artur Jasinski (grafix(AT)csl.pl), Dec 02 2007

Gf.: 1/(1-x)^16. a(n)=C(n,15),n>=15 [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Aug 06 2008]

Gf.: 1/(1-x)^16. - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Aug 03 2008

seq(binomial(n, 15), n=15..37); [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Aug 06 2008]

seq(binomial(n, 15), n=15..37); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Aug 03 2008

Table[n(n+1)(n+2)(n+3)(n+4)(n+5)(n+6)(n+7)(n+8)(n+9)(n+10)(n+11)(n+12)(n+13)(n+14)/15!, {n, 1, 100}] - Artur Jasinski (grafix(AT)csl.pl), Dec 02 2007

Adjacent sequences: A010965 A010966 A010967 this_sequence A010969 A010970 A010971

Sequence in context: A067814 A139616 A059421 this_sequence A022581 A114182 A048533

nonn

njas