|
Search: id:A015910
|
|
| |
|
| 0, 0, 2, 0, 2, 4, 2, 0, 8, 4, 2, 4, 2, 4, 8, 0, 2, 10, 2, 16, 8, 4, 2, 16, 7, 4, 26, 16, 2, 4, 2, 0, 8, 4, 18, 28, 2, 4, 8, 16, 2, 22, 2, 16, 17, 4, 2, 16, 30, 24, 8, 16, 2, 28, 43, 32, 8, 4, 2, 16, 2, 4, 8, 0, 32, 64, 2, 16, 8, 44, 2, 64, 2, 4, 68, 16, 18, 64, 2, 16, 80, 4, 2, 64
(list; graph; listen)
|
|
|
OFFSET
|
1,3
|
|
|
COMMENT
|
a(0) could equally well be taken to be 1.
Certain residues do not appear below exponent n < 10000. E.g. 1,3,5,6,9,.. Also, some [r=12,13,14,15,16] arise first at large exponents [3763,95,1010,481,20]. Do all values eventually appear? - Labos E. (labos(AT)ana.sote.hu), Jan 03 2002
Known solutions to 2^n = 3 (mod n) are given in A050259.
For n an odd prime the sequence is equal to 2. - Paolo P. Lava (ppl(AT)spl.at), Feb 09 2007
|
|
REFERENCES
|
R. K. Guy, Unsolved Problems in Number Theory, F10.
|
|
LINKS
|
T. D. Noe, Table of n, a(n) for n=1..10000
Albert Frank, International Contest Of Logical Sequences, 2002 - 2003. Item 4
Albert Frank, Solutions of International Contest Of Logical Sequences, 2002 - 2003.
Peter L. Montgomery, 65-digit solution.
|
|
MAPLE
|
a:=n->2^n mod(n): seq(a(n), n=1..84); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 15 2008
seq(irem(2^n, n), n=1..84); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Apr 20 2008
|
|
MATHEMATICA
|
Table[PowerMod[2, n, n], {n, 85} ]
|
|
CROSSREFS
|
Cf. A036236, A015911.
Adjacent sequences: A015907 A015908 A015909 this_sequence A015911 A015912 A015913
Sequence in context: A092741 A037036 A055947 this_sequence A023987 A021498 A025251
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Robert G. Wilson v (rgwv(AT)rgwv.com)
|
|
|
Search completed in 0.002 seconds
|