0,2

Since squares are 0 or 1 under both mod 3 and mod 4, for the Pythagorean equation A^2 + B^2 = C^2 to hold, each of 3 and 4 divides either of leg A or leg B, so that area A*B/2 is divisible by 3*4/2=6. a(n)=A024406(n+1)/6. - Lekraj Beedassy (blekraj(AT)yahoo.com), Apr 30 2004

Ron Knott, Pythagorean Triples and Online Calculators

Cf. A020882-A020886.

Sequence in context: A105136 A023494 A015847 this_sequence A004470 A080949 A037977

Adjacent sequences: A020882 A020883 A020884 this_sequence A020886 A020887 A020888

nonn

Clark Kimberling (ck6(AT)evansville.edu)

Extended and corrected by David W. Wilson (davidwwilson(AT)comcast.net)