|
Search: id:A021823
|
|
|
| A021823 |
|
Decimal expansion of 1/819. |
|
+0 12
|
|
| 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1, 2, 2, 1, 0, 0, 1
(list; cons; graph; listen)
|
|
|
OFFSET
|
0,4
|
|
|
COMMENT
|
Partial sums of A010892. - Paul Barry (pbarry(AT)wit.ie), Jun 06 2003
Expansion in any base b >= 3 of 1/((b-1)(b^2-b+1) = 1/(b^3-2b^2+2b-1). E.g., 1/14 in base 3, 1/39 in base 4, 1/84 in base 5, etc. - Franklin T. Adams-Watters (FrankTAW(AT)Netscape.net), Nov 07 2006
|
|
FORMULA
|
a(n) = a(n-1)-a(n-2)+1 = 2-a(n-3) = a(n-6) - Henry Bottomley (se16(AT)btinternet.com), Apr 12 2000
a(n) = Sum_{k=1..floor(n/2)} (-1)^(k+1)*binomial(n-k, k) = 1-((-1)^floor(n/3)+(-1)^(floor((n+1)/3)))/2. - Vladeta Jovovic (vladeta(AT)eunet.rs), Feb 10 2003
G.f.: x^2/(1-2x+2x^2-x^3)=x^2/((1-x)(x^2-x+1)) - Paul Barry (pbarry(AT)wit.ie), Jun 06 2003
a(n+2)=sum{k=0..n, binomial(n-2k, n-k)}; - Paul Barry (pbarry(AT)wit.ie), Jan 15 2005
a(n)=(1/30)*{7*(n mod 6)+7*[(n+1) mod 6]+2*[(n+2) mod 6]-3*[(n+3) mod 6]-3*[(n+4) mod 6]+2*[(n+5) mod 6]}, with n>=0 - Paolo P. Lava (ppl(AT)spl.at), Jan 31 2008
|
|
CROSSREFS
|
Cf. A077859.
Cf. A027444.
Sequence in context: A049783 A024712 A164965 this_sequence A131026 A014604 A015199
Adjacent sequences: A021820 A021821 A021822 this_sequence A021824 A021825 A021826
|
|
KEYWORD
|
nonn,cons
|
|
AUTHOR
|
N. J. A. Sloane (njas(AT)research.att.com).
|
|
|
Search completed in 0.002 seconds
|