id:A023402 - OEIS Search Results

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If any power of 2 ends with k 3's and 4's, they must be the first k elements of this sequence in reverse order.

+0
3

4, 4, 3, 3, 3, 4, 3, 3, 3, 3, 4, 3, 3, 3, 4, 3, 4, 4, 3, 4, 4, 4, 4, 3, 4, 4, 3, 3, 4, 3, 3, 3, 4, 3, 3, 3, 3, 3, 3, 4, 3, 3, 4, 3, 4, 3, 3, 4, 4, 4, 3, 4, 3, 4, 3, 3, 4, 4, 3, 4, 3, 4, 3, 3, 3, 4, 3, 3, 3, 4, 3, 3, 4, 4, 4, 3, 4, 4, 4, 4, 4, 3, 3, 3, 3, 4, 3, 4, 3, 4, 4, 3, 3, 4, 4, 3, 3, 4, 3, 3, 4, 3, 4, 3, 3, 3, 4, 4 (list; graph; listen)

	OFFSET	`0,1`
	COMMENT	`Conjecture: a(n) = 3rd divisor of smallest number having exactly n+2 divisors, a(n)=T(n+2,3), T as defined in A081532. - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jul 18 2003`
	CROSSREFS	`Cf. A035014.` `Sequence in context: A016497 A138160 A120886 this_sequence A073261 A020805 A106147` `Adjacent sequences: A023399 A023400 A023401 this_sequence A023403 A023404 A023405`
	KEYWORD	`nonn`
	AUTHOR	`David W. Wilson (davidwwilson(AT)comcast.net)`

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Last modified December 2 11:54 EST 2009. Contains 167921 sequences.

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