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Search: id:A026363
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| 1, 3, 4, 5, 6, 8, 9, 11, 12, 14, 15, 17, 18, 19, 20, 22, 23, 25, 26, 27, 28, 30, 31, 33, 34, 35, 36, 38, 39, 41, 42, 43, 44, 46, 47, 49, 50, 52, 53, 55, 56, 57, 58, 60, 61, 63, 64, 65, 66, 68, 69, 71, 72, 74, 75, 77, 78, 79, 80, 82, 83, 85, 86
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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Or, starting from the natural number, delete successively from the working sequence the term in position 2*a(n). From natural numbers, delete the term in position 2*1, i.e 2 This leaves 1,3,4,5,6,7,8,9,10,11,. . . Delete now the term in position 2*3=6, i.e 7 This leaves 1,3,4,5,6,8,9,10,11,. . . . Delete now the term in position 2*4=8, i.e 10 This leaves 1,3,4,5,6,8,9,11,. . . . and so on - Philippe Lallouet (philip.lallouet(AT)wanadoo.fr), Aug 20 2007
The term deleted from the n-th working sequence is equal to A026364(n), which means that all integers which are not in the present sequence are in A026364 and no others. - Philippe Lallouet (philip.lallouet(AT)orange.fr), May 05 2008
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FORMULA
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a(1)=1, then a(n)=a(n-1)+2 if n is even and n/2 is not is the sequence, a(n)=a(n-1)+1 otherwise (in particular a(2k+1)=a(2k)+1). a(n)=(1+sqrt(3))/2*n+O(1). Taking a(0)=0, for n>=1 a(2n)-a(2n-2)=A080428(n). - Benoit Cloitre (benoit7848c(AT)orange.fr), Apr 23 2008
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CROSSREFS
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Cf. A026362.
Cf. A079255, A080428.
Sequence in context: A063977 A047428 A039066 this_sequence A124678 A026460 A026464
Adjacent sequences: A026360 A026361 A026362 this_sequence A026364 A026365 A026366
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KEYWORD
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nonn
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AUTHOR
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Clark Kimberling (ck6(AT)evansville.edu)
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