|
Search: id:A031138
|
|
|
| A031138 |
|
1^5+2^5+...+n^5 is a square. |
|
+0 6
|
|
| 1, 13, 133, 1321, 13081, 129493, 1281853, 12689041, 125608561, 1243396573, 12308357173, 121840175161, 1206093394441, 11939093769253, 118184844298093
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
LINKS
|
Eric Weisstein's World of Mathematics, Hex Number
|
|
FORMULA
|
a(n) =11*(a(n-1)-a(n-2)) + a(n-3); a(n)=-1/2+((3-sqrt(6))/4)*(5+2sqrt(6))^n+((3+sqrt(6))/4)*(5-2sqrt(6))^n.
a(n)^2+(a(n)+1)^2=(b(n)-1)^2+b(n)^2+(b(n)+1)^2=c(n)=3d(n)+2; where b(n) is A054320, c(n) is A007667 and d(n) is A006061
a(n) = 10*a(n-1) - a(n-2) + 4; a(0) = a(1) = 1. Also sum of first a(n) fifth powers is a square m^2, where m has factors A000217{a(n)} and A054320(n). - Lekraj Beedassy (blekraj(AT)yahoo.com), Jul 08 2002
contfrac(sqrt(6)/A054320(n))[4]/2 - Thomas Baruchel (baruchel(AT)users.sourceforge.net), Dec 02 2003
|
|
EXAMPLE
|
a(2)=13 because 1^5+2^5+...13^5=1001^2; a(1)=1 because 1^5=1^2
|
|
CROSSREFS
|
Cf. A006061, A054320, A007667.
Sequence in context: A037617 A081042 A016153 this_sequence A097166 A073556 A132935
Adjacent sequences: A031135 A031136 A031137 this_sequence A031139 A031140 A031141
|
|
KEYWORD
|
easy,nonn
|
|
AUTHOR
|
Ignacio Larrosa Canestro (ignacio.larrosa(AT)eresmas.net) entry revised Feb 27 2000
|
|
|
Search completed in 0.002 seconds
|