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A033999 (-1)^n. +0
45
1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1 (list; graph; listen)
OFFSET

0,1

COMMENT

Contribution from Matthew Lehman (matt.comicopia(AT)gmail.com), Nov 17 2008: (Start)

In the Fibonacci sequence, F(n) = F(n-1) + F(n-2),

for every ith number, F(n+i) = A(i)*F(n) + B(i)*F(n-i),

B(i) is given by this sequence,

where B(i) = (-1)^(i+1).

A(i) = F(2*i-1)/F(i-1).

For every Fibonacci number, F(n+1) = F(n) + F(n-1).

For every 2nd Fibonacci number, F(n+2) = 3*F(n) - F(n-2).

For every 3rd Fibonacci number, F(n+3) = 4*F(n) + F(n-3).

For every 4th Fibonacci number, F(n+4) = 7*F(n) - F(n-4).

For every 5th Fibonacci number, F(n+5) = 11*F(n) + F(n-5).

(End) (From Vasiliy Danilov (danilovv(AT)usa.net))

Furthermore requiring F(0) = F(1) = 1, we have a(n) = (-1)^n = F(n)^2 - F(n - 1)F(n + 1), meaning that in trying to convert a square F(n)^2 square units in area into a rectangle F(n - 1) by F(n + 1) square units in area, the square will be deficient by one square unit when n is odd, and have a surplus of one square unit when n is even. (From Alonso Delarte (alonso.delarte(AT)gmail.com), Nov 30 2009)

Let A be the Hessenberg matrix of order n defined by: A[1,j]=1, A[i,i]:=2,(i>1), A[i,i-1]=-1, and A[i,j]=0 otherwise. Then, for n>=1, a(n-1)=charpoly(A,2). [From Milan R. Janjic (agnus(AT)blic.net), Jan 26 2010]

LINKS

Tanya Khovanova, Recursive Sequences

Eric Weisstein's World of Mathematics, Inverse Tangent

Eric Weisstein's World of Mathematics, Stirling Transform

Wikipedia, Grandi's series [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Nov 21 2009]

Index entries for sequences related to linear recurrences with constant coefficients

FORMULA

G.f.: 1/(1+x). E.g.f.: exp(-x). D.g.f.: (2^(1-s)-1)*zeta(s).

Linear recurrence: a(0)=1, a(n)=-a(n-1) for n>0 [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Mar 20 2009]

MAPLE

A033999 := n->(-1)^n;

MATHEMATICA

Table[(-1)^n, {n, 0, 88}]

PROGRAM

(PARI) a(n)=1-2*(n%2) [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Mar 20 2009]

CROSSREFS

Sum_{0<=k<=n} a(k) = A059841(n) [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Nov 21 2009]

Sequence in context: A143622 A076479 A155040 this_sequence A057077 A162511 A157895

Adjacent sequences: A033996 A033997 A033998 this_sequence A034000 A034001 A034002

KEYWORD

sign,easy,new

AUTHOR

Vasiliy Danilov (danilovv(AT)usa.net) Jun 15 1998

EXTENSIONS

Comment on Fibonacci square unit creation fallacy and Mathematica command added by Alonso Delarte (alonso.delarte(AT)gmail.com), Nov 30 2009

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Last modified February 9 11:24 EST 2010. Contains 172296 sequences.


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